不能在php Mysql中使用mysqli_result类型的对象作为数组
[英]Cannot use object of type mysqli_result as array in php Mysql
问题描述
I want to select the last row for my database and echo the columns titled s1 and s2 to the body of the web page, the following is my code.
我想为我的数据库选择最后一行，并将标题为 s1 和 s2 的列回显到网页正文中，以下是我的代码。 This gives an error.这给出了一个错误。
<html>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb2";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
$row = array();
$row = mysqli_query($conn,$sql);
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
?>
</body>
</html>
3 个解决方案
解决方案1
2 2016-04-29 03:26:15
You have to use mysqli_fetch_assoc (that will loop through your resultset) as follows:您必须使用 mysqli_fetch_assoc（它将遍历您的结果集），如下所示：
if ($result = mysqli_query($conn, $sql)) {
while ($row = mysqli_fetch_assoc($result)) {
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
/* free result set */
mysqli_free_result($result);
}
Without loop:无循环：
if ($result = mysqli_query($conn, $sql)) {
$row = mysqli_fetch_assoc($result);
if($row)
{
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
/* free result set */
mysqli_free_result($result);
}
解决方案2
0
Your solution您的解决方案
<html>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb2";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("MySQL Connection Error"); // Try not to output SQL error messages on the front-end, look into error_reporting()
}
$sqlQuery = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
$results = mysqli_fetch_assoc(mysqli_query($conn, $sqlQuery));
echo " cup 1". $results["s1"]. "CUP 2". $results["s2"];
?>
</body>
</html>
In addition to that, I suggest not doing your SQL operations in both procedural style and object-oriented style, as this can lead to many complications in the future.除此之外，我建议不要同时以过程风格和面向对象风格进行 SQL 操作，因为这可能会导致未来的许多复杂情况。
解决方案3
0 2016-04-29 03:35:48
Use mysqli_fetch_assoc for fetching the result to array使用mysqli_fetch_assoc获取结果到数组
$sql = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
if ($result = mysqli_query($conn, $sql)) {
$row = mysqli_fetch_assoc($result);
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.