[英]Cannot use object of type mysqli_result as array in php Mysql
我想为我的数据库选择最后一行，并将标题为 s1 和 s2 的列回显到网页正文中，以下是我的代码。 这给出了一个错误。
<html>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb2";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
$row = array();
$row = mysqli_query($conn,$sql);
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
?>
</body>
</html>
您必须使用 mysqli_fetch_assoc（它将遍历您的结果集），如下所示：
if ($result = mysqli_query($conn, $sql)) {
while ($row = mysqli_fetch_assoc($result)) {
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
/* free result set */
mysqli_free_result($result);
}
无循环：
if ($result = mysqli_query($conn, $sql)) {
$row = mysqli_fetch_assoc($result);
if($row)
{
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
/* free result set */
mysqli_free_result($result);
}
<html>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb2";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("MySQL Connection Error"); // Try not to output SQL error messages on the front-end, look into error_reporting()
}
$sqlQuery = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
$results = mysqli_fetch_assoc(mysqli_query($conn, $sqlQuery));
echo " cup 1". $results["s1"]. "CUP 2". $results["s2"];
?>
</body>
</html>
除此之外，我建议不要同时以过程风格和面向对象风格进行 SQL 操作，因为这可能会导致未来的许多复杂情况。
使用mysqli_fetch_assoc获取结果到数组
$sql = "SELECT s1, s2 from reading ORDER BY id DESC LIMIT 1";
if ($result = mysqli_query($conn, $sql)) {
$row = mysqli_fetch_assoc($result);
echo " cup 1". $row["s1"]. "CUP 2". $row["s2"];
}
mysqli错误：无法将mysqli_result类型的对象用作数组
[英]mysqli error : Cannot use object of type mysqli_result as array
Mysqli依靠php“不能将mysqli_result类型的对象用作数组”
[英]Mysqli count on php “Cannot use object of type mysqli_result as array”
sql + php-致命错误：无法将mysqli_result类型的对象用作数组，为什么
[英]sql + php - Fatal error: Cannot use object of type mysqli_result as array why
PHP：未捕获的错误无法将类型为mysqli_result的对象用作数组
[英]PHP: Uncaught Error Cannot use object of type mysqli_result as array
使用mysqli-> fetch_assoc（）-无法将mysqli_result类型的对象用作数组
[英]Using mysqli->fetch_assoc() - Cannot use object of type mysqli_result as array
致命错误：无法在第97行上将mysqli_result类型的对象用作数组。
[英]Fatal error: Cannot use object of type mysqli_result as array in…on line 97
致命错误：不能将mysqli_result类型的对象用作C：\\ xampp \\中的数组
[英]Fatal error: Cannot use object of type mysqli_result as array in C:\xampp\
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.