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Laravel 查询生成器原始 AND 语句

[英]Laravel query builder raw AND statement

I need to run a raw SQL query part in Laravel.我需要在 Laravel 中运行原始 SQL 查询部分。

The raw SQL would look basically like this:原始 SQL 基本上如下所示:

AND (forretningsadresse_fylke = 'HEDMARK' 
    AND (forretningsadresse_kommune = 'HAMAR') 
    OR (forretningsadresse_kommune = 'ELVERUM')
) 
OR (forretningsadresse_fylke = 'HORDALAND' 
    AND (forretningsadresse_kommune = 'BERGEN')
) 

I try to use:我尝试使用:

$result = Company::where(function($a) use($input, $sql) {

        // Name or keywords LIKE string
        $a -> where('navn', 'LIKE', '%'. $input['query_string'] .'%');
        $a -> where('keywords', 'LIKE', '%'. $input['query_string'] .'%');
        if (!empty($sql)) {
            $a -> where(DB::statement($sql));
        }

    });

    $result = $result -> take($input['limit'])       // Take $limit
                      -> offset($input['offset'])    // Offset by $offset
                      -> orderBy('rank', 'DESC')     // Sponsors first
                      -> get();  

But it doesn't work.但它不起作用。 See the error below.请参阅下面的错误。 How would I get this to work?我如何让这个工作? Thanks in advance!提前致谢!

QueryException in Connection.php line 673: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; Connection.php 第 673 行中的 QueryException:SQLSTATE[42000]:语法错误或访问冲突:1064 您的 SQL 语法有错误; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AND (forretningsadresse_fylke = 'AKERSHUS')' at line 1 (SQL: AND (forretningsadresse_fylke = 'AKERSHUS') )检查与您的 MariaDB 服务器版本相对应的手册,了解在第 1 行的“AND (forretningsadresse_fylke = 'AKERSHUS')' 附近使用的正确语法(SQL: AND (forretningsadresse_fylke = 'AKERSHUS'))

EDIT: The table has 1 million rows, and I use this method to create the raw query: http://i.imgur.com/Q5SRP58.png编辑:该表有 100 万行,我使用此方法创建原始查询: http : //i.imgur.com/Q5SRP58.png

There are two issues with your code:您的代码有两个问题:

  1. You are using DB::statement where you should be using DB::raw .您在应该使用DB::raw地方使用DB::statement DB::statement will execute the string that you pass as an argument and that is not what you need. DB::statement将执行您作为参数传递的字符串,这不是您需要的。 You need to pass a raw statement to be included to the query builder.您需要传递要包含到查询构建器的原始语句。
  2. Assuming the raw block you posted is the $sql parameter, then you need to remove the starting AND , otherwise the query will end up with .... and AND ( , which will throw an error.假设您发布的原始块是$sql参数,那么您需要删除起始AND ,否则查询将以.... and AND ( ,这将引发错误。

Given this, you need to update your code to:鉴于此,您需要将代码更新为:

// Notice the removal of the `AND`
$sql = "(forretningsadresse_fylke = 'HEDMARK' 
        AND (forretningsadresse_kommune = 'HAMAR') 
        OR (forretningsadresse_kommune = 'ELVERUM')
    ) 
    OR (forretningsadresse_fylke = 'HORDALAND' 
        AND (forretningsadresse_kommune = 'BERGEN')
    )";

$result = Company::where(function($a) use($input, $sql) {
    // Name or keywords LIKE string
    $a->where('navn', 'LIKE', '%'. $input['query_string'] .'%');
    $a->where('keywords', 'LIKE', '%'. $input['query_string'] .'%');
    if (!empty($sql)) {
        // Using DB::raw instead of DB::statement
        $a->where(DB::raw($sql));
    }
});

Try尝试

$result = Company::where('navn', 'LIKE', '%'. $input['query_string'] .'%')
    ->where('keywords', 'LIKE', '%'. $input['query_string'] .'%')
    ->where(function($query){
        $query->where('forretningsadresse_fylke', '=', 'HEDMARK' )
              ->where('forretningsadresse_kommune', '=', 'HAMAR')
              ->orWhere('forretningsadresse_kommune','=', 'ELVERUM');
    })
    ->where(function($query){
        $query->orWhere('forretningsadresse_fylke','=', 'HORDALAND')
              ->where('forretningsadresse_kommune', '=', 'BERGEN');
   })
   ->take($input['limit'])       // Take $limit
   ->offset($input['offset'])    // Offset by $offset
   ->orderBy('rank', 'DESC')     // Sponsors first
   ->get();  

hope it helps希望能帮助到你

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