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任何说明子列表[即某物] 是否存在于列表中的函数？

[英]Any function which says if a sublist[i.e. something] exists inside a list or not?

原文 2016-05-03 20:53:40 1 1 python/ python-2.7

Is there any simple function which says if a sub-list [ie Something or Anything] exits within a list or not ?是否有任何简单的函数可以说明子列表 [即某物或任何东西] 是否存在于列表中？

For Example: a.例如： a. Says there is a top list, ie top_list = [] b.说有一个顶级列表，即top_list = [] b。 Next check if some sub-list exits or not ie if top_list[0] exits or not ?接下来检查某些子列表是否存在，即 top_list[0] 是否存在？ Something like, top_list is [[]].就像，top_list 是 [[]]。 That sub-list can be just an empty list [] or a list with some number etc..该子列表可以只是一个空列表 [] 或带有一些数字等的列表。

Just wanted to find if a sub-list exits within a list or not ?只是想查找子列表是否存在于列表中？ Kindly drop in your comments if you have any suggestions.如果您有任何建议，请留下您的意见。

Thanks in Advance, Vimo提前致谢， Vimo

1 个解决方案

This: https://stackoverflow.com/a/5148526/6194839 will check for a non-sequential list.这个： https : //stackoverflow.com/a/5148526/6194839将检查非顺序列表。

Checking for a sequential list I would just brute force it, looking through the list for an entry that matches the first in your sub-list, then checking for the rest.检查顺序列表我只会强制执行它，在列表中查找与子列表中的第一个匹配的条目，然后检查其余的条目。