如何对浮点值排序？

Question

I want to sort a big ascii file. Example:

-10
+9.9
-1.003
-6
4.01

sort -n gives:

-1.003         # -1.003 is bigger than -10
-10            #
-6
+9.9
4.01

Is there any solution for this?

Answer 1

Use -g instead of -n :

sort -g file

It returns:

-10
-6
-1.003
4.01
+9.9

From man sort :

   -g, --general-numeric-sort
          compare according to general numerical value

Answer 2

问题似乎是+ charachter ...也许您可以像这样过滤+ charachter：

less yourfile | tr -d '+' | sort -n