[英]MySQL, PHP: Select * from table where id is not in array
so I currently have a database table where I am trying to select all of the records EXCEPT for those that are included in an array that I have made. 所以我目前有一个数据库表,我试图选择所有记录除了那些包含在我已经制作的数组中的记录。 As some background context:
作为一些背景背景:
The structure of the database table in question is: 有问题的数据库表的结构是:
server_status:
id int(11)
server_id int(11)
time_checked datetime
status char(1)
My PHP script to get the data into the hash looks like this: 将数据导入哈希的PHP脚本如下所示:
$sql2 = "SELECT server_id, time_checked,id from server_status where time_checked<'$date' order by server_id;";
$result2=$conn->query($sql2);
while($row2 = $result2->fetch_assoc()){
$server_id = $row2['server_id'];
$id = $row2['id'];
$dt = $row2['time_checked'];
$year = substr($dt,0,4);
$month = substr($dt,5,2);
$day = substr($dt,8,2);
$day = "$year-$month-$day";
$all[$server_id][$day] = $id; // ARRAY
}
So what I'm trying to do is create a MySQL query that reads in the ids ($id) from the array, and selects * APART from that. 所以我要做的是创建一个MySQL查询,从数组中读取id($ id),并从中选择* APART。 From looking it up, it seems like I will have to use a 'where not' clause, but I do not know how to reference the hash in this.
从查找起来,似乎我将不得不使用'where not'子句,但我不知道如何引用哈希。
Further clarification: I now have an array which extracts data which looks like this: 进一步澄清:我现在有一个数组,它提取如下所示的数据:
1{
2016-05-05 : 252
2016-05-10 : 406
2016-04-27 : 141
2016-05-04 : 164
2016-05-09 : 263
2016-05-03 : 153
2016-04-26 : 131
2016-04-14 : 1
2016-04-18 : 31
2016-04-21 : 111
2016-04-20 : 61
2016-04-19 : 51
2016-04-15 : 21
2016-04-25 : 121
}
2{
2016-05-10 : 452
2016-05-05 : 198
2016-05-09 : 264
2016-05-04 : 165
2016-04-26 : 132
2016-04-27 : 143
2016-04-25 : 122
2016-04-21 : 112
2016-05-03 : 154
}
I want to take the IDs from this array (eg 154) and select everything in the table which doesn't have any of the above IDs. 我想从这个数组中获取ID(例如154)并选择表中没有任何上述ID的所有内容。 I hope this helps to clarify?!
我希望这有助于澄清?!
Any help will be greatly appreciated! 任何帮助将不胜感激!
In case $all
is the array you want to extract the unwanted ids from, this might be what you need after the code you provided: 如果
$all
是要从中提取不需要的ID的数组,这可能是您提供的代码后所需的内容:
$ids_to_exclude = array();
// iterate through servers
foreach ($all as $server_id => $dates) {
// iterate through dates of each server
foreach ($dates as $date => $id) {
// If a value is not in the array, add it.
// In case ids don't repeat, you won't need this if
if (!in_array($id, $ids_to_exclude)) {
// add $id to the array
$ids_to_exclude[] = $id;
}
}
}
$sql_condition = "where `id` not in (".implode(",",$ids_to_exclude).")";
Just be careful when writing queries with string concatenation. 使用字符串连接编写查询时要小心。 Read about SQL Injection and how to prevent it.
阅读有关SQL注入以及如何防止它的信息。 Use Prepared Statements instead of pure concatenation.
使用准备语句而不是纯连接。
I think you just want a NOT IN, right? 我想你只想要一个NOT IN,对吗?
$sql2 = "SELECT id, server_id, time_checked,id
FROM server_status
WHERE
id NOT IN (".implode(',', $id_array)."
AND time_checked<'$date'
ORDER BY server_id;";
$result2=$conn->query($sql2);
while($row2 = $result2->fetch_assoc()){
$server_id = $row2['server_id'];
$id = $row2['id'];
$dt = date('Y-m-d', strtotime($row2['time_checked']));
$all[$server_id][$dt] = $id; // ARRAY
}
SOLVE: 解决:
$sql2 = "SELECT server_id, time_checked,id from server_status where time_checked<'$date' order by server_id;";
$result2=$conn->query($sql2);
while($row2 = $result2->fetch_assoc()){
while($row2 = $result2->fetch_assoc()){
$server_id = $row2['server_id'];
$id = $row2['id'];
$dt = date('Y-m-d', strtotime($row2['time_checked']));
$all[$server_id][$dt] = $id; // ARRAY
}
}
$stack = array();
$keys = array_keys($all);
for($i = 0; $i < count($all); $i++) {
foreach($all[$keys[$i]] as $key => $value) {
array_push($stack, $value);
}
}
$ids = join(',',$stack);
$sql = "SELECT * FROM server_status WHERE time_checked<'$date' AND id NOT IN ($ids)";
$result=$conn->query($sql);
echo "Server status data has been deleted.<br>";
Created another array from the multi-dimensional array to store the ids only and use NOT IN like John Green suggested. 从多维数组中创建另一个数组以仅存储id,并使用像John Green建议的NOT IN。
Thanks! 谢谢!
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