PHP mysqli SELECT * from my_table哪里ID = array_of_ids

Question

I have been using this site for years now and this is the first time I'm asking a question here, so kinda scared right now :D

Here's what my problem is, I have got two tables. In table_a I got three columns and in table_b I got 5. So the setup right now looks something like this:

       table_a

| r_id | foo   | bar |
+------+-------+-----+
| 1    | dude  | 5   |
+------+-------+-----+
| 2    | homie | 6   |
+------+-------+-----+
| 3    | bro   | 7   |
+------+-------+-----+

       table_b

| id | ada   | rea | lm   | cor  |
+----+-------+-----+------+------+
| 5  | ching | ink | jk   | 32.4 |
+----+-------+-----+------+------+
| 1  | momo  | pal | lmao | 95.5 |
+----+-------+-----+------+------+
| 6  | mama  | pen | lol  | 26.9 |
+----+-------+-----+------+------+
| 4  | chac  | pin | fun  | 91.2 |
+----+-------+-----+------+------+
| 7  | chim  | lap | funk | 82.4 |
+----+-------+-----+------+------+
| 9  | cho   | kil | fin  | 38.1 |
+----+-------+-----+------+------+

Now what I'm trying to do is to get all the data from table_a and then only get lm from table_b. I'm getting all the data from table_a like this:

SELECT r_id, foo, bar from table_a

I need to use the ids I get from bar column to get lm from table_b. So is there a way I can pass an array to only get the data based on the ids in an array? If not, then what would be the most efficient way to get those?

The output I'm expecting is jk, lol, funk . Would appreciate any help, thanks!

Answer 1

You should be looking at using a JOIN to link the two tables together in 1 query...

SELECT  r_id, foo, bar, lm
    FROM table_a 
    JOIN table_b on bar = id

Answer 2

Why not join?

select group_concat(lm) as lm_list
from table_b b
inner join table_a a on b.id = a.bar

You can use the GROUP_CONCAT() function, with this you would get jk, lol, funk otherwise you would get 3 rows each of one lm value,

Answer 3

For that you can try WHERE IN feature of SQL.

SELECT lm from table_b WHERE id IN(ARRAY_OF_IDS)

Or you can also use join to achieve this

Select tale_a.*, tale_b.lm from tale_a inner join table_b ON tale_a.bar=tale_b.id

Answer 4

尝试inner join

SELECT a.r_id, a.foo, a.bar, b.lm  from table_a as a inner join table_b as b on b.id=a.bar

Answer 5

You can use INNER JOIN

 SELECT tale_a.r_id, tale_a.foo, tale_a.bar ,table_b.lm 
 FROM tale_a
 INNER JOIN table_b
 ON tale_a.bar=table_b.id

Note: It returns all columns from table_a and only one column from table_b

Resultant Output:

| r_id | foo   | bar | lm  |
+------+-------+-----+-----+
| 1    | dude  | 5   | jk  |
+------+-------+-----+-----+
| 2    | homie | 6   |lol  |
+------+-------+-----+-----+
| 3    | bro   | 7   |funk |
+------+-------+-----+-----+

Answer 6

I assume that you have array of IDs having IDs. So first make a comma separated string of that array of IDs like this:

ids_str = implode("," $ARRAY_OF_IDS);

and then use that ids_str in IN os mysql query like below:

SELECT lm from table_b WHERE id IN( ids_str )