[英]SQL Transform Crosstab Pivot Data
I am using SQL Server 2008 and would like to transform my data such that: 我正在使用SQL Server 2008,并且希望将数据转换为:
Dataset: 数据集:
ID Item Columns Result
1 1 X A
2 1 Y B
3 1 Z C
4 2 X D
5 2 Y E
6 2 Z NULL
7 3 X F
8 3 Y G
9 3 Z H
Results Desired: 所需结果:
Item X Y Z
1 A B C
2 D E NULL
3 F G H
At this time, I am doing the following, then pasting the columns I need into Excel: 目前,我正在执行以下操作,然后将所需的列粘贴到Excel中:
Select * from thisTable where Column=X
Select * from thisTable where Column=Y
Select * from thisTable where Column=Z
However, not all of the rows match up to can can't just smack the tables side by side. 但是,并非所有匹配的行都不能仅仅并排击打表。 For columns without a Result, I'd like NULL to show up to fill in the rows to make them all the same number of records.
对于没有Result的列,我希望显示NULL来填充行以使它们都具有相同数量的记录。
I looked up PIVOT but I don't think this works here...what is this type of data transformation called? 我查了一下PIVOT,但我认为这在这里不起作用...这种数据转换称为什么类型? I don't think it's a crosstab...
我不认为这是交叉表...
Thanks! 谢谢!
You can do a crosstab using conditional aggregation: 您可以使用条件聚合来执行交叉表:
SELECT
Item,
[X] = MAX(CASE WHEN [Columns] = 'X' THEN Result END),
[Y] = MAX(CASE WHEN [Columns] = 'Y' THEN Result END),
[Z] = MAX(CASE WHEN [Columns] = 'Z' THEN Result END)
FROM thisTable
GROUP BY Item
use PIVOT 使用PIVOT
select *
from (
select Item, Columns, Result
from thisTable
) t
pivot (
max (Result)
for Columns in (X, Y, Z)
) p
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