正则表达式匹配最后一个字符

Question

data:text/javascript;base64,Ly8gSGVyZdsdsd:5
data:text/javascript;base64,Ly8gSGVyZdsdsd:2
data:text/javascript;base64,Ly8gSGVyZdsdsd:1

I want to select the second line of text above using regex. How to catch end of string of 2 here? I'm stuck.

^.*$

Answer 1

You can use a very simple pattern

string.match(/.*2$/m)
=> ["data:text/javascript;base64,Ly8gSGVyZdsdsd:2"]

Answer 2

.$ Short explenation. . means any character, or every non-whitespace character, and it should be the last one. This is because of $ which means it should be the last thing.

Now just implement it in your favoritt language ex. js:

var string = "hello world!"; Var match = string.match(/.$/);

(Not sure if match now has the value of "!" Or only a boolean value, js not my strongest language)