正则表达式匹配的最后一个字符

Question

I am trying to use a regex to detect a pattern in the current page query string.

For this reason I have the following regex:

var re = new RegExp("([?|&])" + key + "=.*?(&|#|$)", "i");

I am testing it against this input:

http://127.0.0.1:33822/?year=2015&country=Portugal&format=psd

And it works just fine finding the pattern.

What I am really trying to get is the last character index relative to the whole URL.

So for example if I want the index o the last 'd' character:

http://127.0.0.1:33822/?year=2015&country=Portugal&format=ps**d**

In this specific case I would want 60.

Thanks in advance

Answer 1

You can use match.index for that. It will give you where the match exists in the original string. Then you can use the matche[0].length to find the last character in the match

 key='format'
 re = new RegExp("([?|&])" + key + "=.*?(&|#|$)", "i");
 url='http://127.0.0.1:33822/?year=2015&country=Portugal&format=psd'

match=url.match(re)

console.log(match.index + match[0].length-1) // 60