如何使用PHP在嵌套的if-else条件下继续进行外部while循环？

Question

I have a piece of code as following:

while ( $conver = mysqli_fetch_assoc($converQ)) // for each conversation
{
    $group_mark = array();

    if ($conver['send_from'] == 1)  // send from group
    {  
        if (in_array($conver['sender_id'], $group_mark)) 
        {
            continue;
        }
        else
        {
            array_push($group_mark, $conver['sender_id']);
        }
     ...

In the beginning of the while-loop , I have to check whether the conversation is from group or individual. If it is from group, I should check whether the id has appeared or not. But now the continue can not stop executing the following code in the while-loop and start the next loop. I think the reason is that its outer function is if-else but not the while-loop directly. Could you please tell me how to edit the code to do what I want? Thank you in advance!

EDIT:

I have tried this: continue 2 but it doesn't work. Why?

Thanks to @ThinkingMedia, I know what's the problem now. I put the $group_mark in the wrong place. Sorry.

Answer 1

In these cases which you want to stop check other rows you can develop a function and return as true in the location which you need:

function check()
{
    while ( $conver = mysqli_fetch_assoc($converQ)) // for each conversation
    {
     $group_mark = array();

     if ($conver['send_from'] == 1)  // send from group
     {  
         if (in_array($conver['sender_id'], $group_mark)) 
         {
            return true;
         }
         else
         {
             array_push($group_mark, $conver['sender_id']);
         }
     }
   }
 }

Answer 2

Your code is right. But continue does not jump off those if/else statements.

In php docs they say is deprecated: continue {var}

5.4.0 Removed the ability to pass in variables (eg, $num = 2; continue $num;) as the numerical argument.

You can modify your code as follows:

while ( $conver = mysqli_fetch_assoc($converQ)) // for each conversation
{
    $group_mark = array();

    if ($conver['send_from'] == 1)  // send from group
    {  
        if (!in_array($conver['sender_id'], $group_mark)) {
            array_push($group_mark, $conver['sender_id']);
        }
    }
    ...
}

Answer 3

Found some interesting, curious about why your $group_mark = array(); is in the while loop. It seem like this will get overwrited and will not able to hit the if condition, because of the group_mark always is empty array.

Try to move this to before of your while loop. This should solve and get what you need.