在列表中获得最高价值的卡

Question

I have a list of cards:

    hand = ["KC", "QC", "4C", "0S"]

And I always want to get the highest card in terms of rank, like in this list

    rank_cards = ["2", "3", "4", "5", "6", "7", "8", "9", "0", "J", "Q", "K", "A"]

The highest card in this case would be:

    "KC"

How can I do this for any sort of hand I get?

I was thinking of using a dictionary to rank cards in terms of index, like this:

    d = {}
    for i, c in enumerate(rank_cards):
        d[c] = i

Is there a better way to do this?

Thanks

Answer 1

You could use the max built-in function and use a custom key function.

>>> max(hand, key=lambda c: rank_cards.index(c[0]))
'KC'

If you want to sort the entire hand in descending order based on rank

>>> hand.sort(key=lambda c: rank_cards.index(c[0]), reverse=True)

If you wanted slightly better performance by pre-computing indexes (basically, your solution, but one-lined in a dictionary comprehension).

>>> rank_cards_map = {c: i for i, c in enumerate(rank_cards)}
>>> max(hand, key=lambda c: rank_cards_map[c[0]])