[英]Find highest value in a list with For loop
I have a list of scores, and I'd like to find the highest values in the list (in my example below, it is the value 80).我有一个分数列表,我想找到列表中的最高值(在下面的示例中,它是值 80)。
scores = [60,29,60,43,10,9,80,45,23,80,56,4]
highest_score = 0
for i in scores:
if i >= highest_score:
highest_score = i
print (highest_score, scores.index(highest_score) )
For highest_scores
, it returns [60,60,80,80]
, whereas I'd like to get only the highest value 80
.对于最高得分,它返回[60,60,80,80]
highest_scores
而我只想获得最高值80
。 For scores.index(highest_score)
, it is giving me the indexes [0,0,6,6]
, whereas I'd like to get the indexes of the highest value - that should be [6,6]
.对于scores.index(highest_score)
,它给了我索引[0,0,6,6]
,而我想获得最高值的索引 - 那应该是[6,6]
。
How can I improve my code to get the desired outcome?如何改进我的代码以获得预期的结果?
If you're looking for the indexes of the highest values in [60,29,60,43,10,9,80,45,23,80,56,4]
, I think you mean you want: [6, 9]
.如果您正在寻找[60,29,60,43,10,9,80,45,23,80,56,4]
中最高值的索引,我认为您的意思是您想要: [6, 9]
.
Assuming that you want a "native" implementation of the algorithm without having to resort to the max()
function, and that you want the indexes I recommend you use enumerate(scores)
:假设您想要算法的“本机”实现而不必求助于max()
function,并且您想要我建议您使用的索引enumerate(scores)
:
scores = [60,29,60,43,10,9,80,45,23,80,56,4]
highest_score = scores[0]
indexes = []
for i, s in enumerate(scores):
if s > highest_score:
indexes = []
if s >= highest_score:
indexes.append(i)
highest_score = s
print(highest_score, indexes)
Result:结果:
80 [6, 9]
You can find max value by:您可以通过以下方式找到最大值:
max(scores)
Returns 80
.返回80
。
The mistake you are doing is in the indentation for print statement.您正在做的错误是在 print 语句的缩进中。 It should be outside the loop.它应该在循环之外。 Try the below code:试试下面的代码:
scores = [60, 29, 60, 43, 10, 9, 80, 45, 23, 80, 56, 4]
highest_score = 0
for i in scores:
if i >= highest_score:
highest_score = I
# find all indices of the highest_score
indices = [i for i, x in enumerate(scores) if x == highest_score]
print(highest_score, indices)
I have also written a list comprehension for finding all the indices of the highest score in the list, as your code would only return the index of the first occurrence.我还编写了一个列表理解,用于查找列表中最高分的所有索引,因为您的代码只会返回第一次出现的索引。
Output: Output:
80 [6, 9]
There are better ways to do it, however since you want to do it using for loops, this should work:有更好的方法可以做到这一点,但是由于您想使用 for 循环来做到这一点,这应该可以:
scores = [60,29,60,43,10,9,80,45,23,80,56,4]
highest_score = 0
index_list = []
for i in scores:
if i >= highest_score:
highest_score = i
for i in scores:
if i == highest_score:
index_list.append(scores.index(i))
print (highest_score , index_list )
Output: Output:
>>> 80 [6, 6]
You can try:你可以试试:
scores = [60,29,60,43,10,9,80,45,23,80,56,4]
highest_score = 0
highest_score_index=[]
for index, score in enumerate(scores):
if score > highest_score:
highest_score = score
highest_score_index.clear()
highest_score_index.append(index)
elif score == highest_score:
highest_score_index.append(index)
print (highest_score, highest_score_index )
for single for loop.对于单个 for 循环。
Returns: 80 [6, 9]
返回: 80 [6, 9]
scores = [60,29,60,43,10,9,80,45,23,80,56,4]
highest_score = None
highest_score_indexes = []
for index, value in enumerate(scores):
if index == 0:
highest_score = value
highest_score_indexes.append(index)
else:
if highest_score > value:
pass
elif highest_score == value:
highest_score_indexes.append(index)
elif highest_score < value:
highest_score = value
highest_score_indexes = [index]
print("heighest score {}".format(highest_score))
print("heighest score indexes {}".format(highest_score_indexes`enter code here`))
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