C＃：使用int和hex值创建一个字节数组

Question

I need to create a an byte array with hex and int values.

For example:

int value1 = 13;
int value2 = 31;
byte[] mixedbytes = new byte[] {0x09, (byte)value1, (byte)value2};

Problem: The 31 is converted to 0x1F. It should be 0x31. I've tried to convert the int values to string and back to bytes but that didn't solve the problem. The integers have never more than two digits.

Answer 1

Try this:

int value1 = 0x13;
int value2 = 0x31;
byte[] mixedbytes = new byte[] { 0x09, (byte)value1, (byte)value2 };

Also, you don't seem to understand conversion between decimal and hex. 31 in decimal is 1F in hex, expecting it to be 31 in hex is a bad expectation for a better understanding of the conversion between decimal and hex, please have a look here: http://www.wikihow.com/Convert-from-Decimal-to-Hexadecimal

Answer 2

I think you can try this method

    string i = "10";
    var b =  Convert.ToByte(i, 16)

In this method 10 will be stored as 0x10

Answer 3

This format is commonly known as Binary Coded Decimal (BCD). The idea is that the nibbles in the byte each contain a single decimal digit.

In C#, you can do this conversion very easily:

var number = 31;
var bcd = (number / 10) * 16 + (number % 10);