C#：Int 到 Hex 字节转换以写入 Hex 文件

Question

I'm having problems in converting an integer into a byte array in hex format to write into my Hex File. I have read and tried several solutions that I went over in here and in many other sites.

I read the integer from the textbox and convert it into an int like that:

int value= int.Parse(textEditValue.EditValue.ToString());

An example input of this number is like:

int value= 568

And I need to write into the hex file like that:

38 36 35 //reversed version of 568 because of endiannes

What I have tried is:

byte[] intBytes = BitConverter.GetBytes(value);
Array.Reverse(intBytes); // Because the hex-file is little-endian
byte[] resultBytes = intBytes;

When the above code runs it writes into the hex file like:

38 02 00 00

How I wrote into the file:

    for(int i = 0x289C; i >= 0x289C - resultBytes.Length; i--)
   {
        binaryWriter.BaseStream.Position = i;
        binaryWriter.Write(resultBytes[count]);
        count++;
    }

I appreciate any help or suggestion.

Answer 1

Your code is correct for converting an integer to hex.

The hex representation of 568 is 00 00 02 38 - so reversed for little Endian, you end up with what you got.

To get your desired output you need to view it, not as integer, but as an ASCII string. If you need to make sure the text input can be converted to an integer, you can do something like this:

if (int.TryParse(textEditValue.EditValue.ToString(), out int myInt)){
    byte[] intBytes = Encoding.ASCII.GetBytes(textEditValue.EditValue.ToString());
    Array.Reverse(intBytes); // Because the hex-file is little-endian
    byte[] resultBytes = intBytes;
}
else {
    //Not a valid integer
}