Python 中是否有一种方法可以在不使用 os.walk、glob 或 fnmatch 的情况下递归搜索目录、子目录和文件？

Question

I know that using these modules makes life a lot easier but as I learn Python, I want to be able to solidify the foundation and then go onto the shortcuts. That way, when presented with the bigger issue, I can analyze and solve it.

I want to be able to return the number of total folders and files in 1 directory such as directory F:\\

I have come up with:

import os

def fcount(path):
  count = 0
  for f in os.listdir(path):
    file = os.path.join(path, f)
    if os.path.isdir(file):
      file_count = fcount(file)
      count += file_count + 1

  for f in os.listdir(path):
    if os.path.isfile(os.path.join(path, f)):
      count += 1
  return count

path = 'F:\\'
print(fcount(path))

This is the final answer. This gives you the total number of subdirectories and files within the specified directory.

Answer 1

You cannot get the number of all files under a directory (recursively) without using os.walk or something that uses the same thing.

This information requires this job and you cannot do it another way. Obviously that there are other libraries that are doing a similar job with some variations but the point is that's the mainly the same thing.

Answer 2

This is the code to do just as os.walk would do. It's manual recursion.

import os

def fcount(path):
    count = 0
    for f in os.listdir(path):
        file = os.path.join(path, f)
        if os.path.isdir(file):
            file_count = fcount(file)
            count += file_count + 1

    for f in os.listdir(path):
        if os.path.isfile(os.path.join(path, f)):
        count += 1
    return count

path = 'F:\\'
print(fcount(path))

Note: Initially in OP, there was no second loop.