用bash替换'源文件'及其内容和扩展变量

Question

In a script.sh,

source a.sh
source b.sh

CMD1
CMD2
CMD3

how can I replace the source *.sh with their content (without executing the commands)? I would like to see what the bash interpreter executes after sourcing the files and expanding all variables.

I know I can use set -n -v or run bash -n -v script.sh 2>output.sh , but that would not replace the source commands (and even less if a.sh or b.sh contain variables).

I thought of using a subshell, but that still doesn't expand the source lines. I tried a combination of set +n +v and set -n -v before and after the source lines, but that still does not work.

I'm going to send that output to a remote machine using ssh. I could use <<output.sh to pipe the content into the ssh command, but I can't log as root onto the remote machine, but I am however a sudoer. Therefore, I thought I could create the script and send it as a base64-encoded string (using that clever trick ) base64 script | ssh remotehost 'base64 -d | sudo bash' base64 script | ssh remotehost 'base64 -d | sudo bash'

Is there a solution? Or do you have a better idea?

Answer 1

You can do something like this:

inline.sh:

#!/usr/bin/env bash
while read line; do
    if [[ "$line" =~ (\.|source)\s+.+ ]]; then
        file="$(echo $line | cut -d' ' -f2)"
        echo "$(cat $file)"
    else
      echo "$line"
    fi
done < "$1"

Note this assumes the source d files exist, and doesn't handle errors. You should also handle possible hashbangs. If the sourced files contain themselves source , you need to apply the script recursively, eg something like (not tested):

while egrep -q '^(source|\.)' main.sh; do
    bash inline.sh main.sh > main.sh
done

Let's test it

main.sh:

source a.sh
. b.sh

echo cc
echo "$var_a $var_b"

a.sh:

echo aa
var_a="stack" 

b.sh:

echo bb
var_b="overflow"

Result:

bash inline.sh main.sh

echo aa
var_a="stack"
echo bb
var_b="overflow"

echo cc
echo "$var_a $var_b"

bash inline.sh main.sh | bash

aa
bb
cc
stack overflow

BTW, if you just want to see what bash executes, you can run

bash -x [script]

or remotely

ssh user@host -t "bash -x [script]"