在case sql语句中使用sum和count

Question

I want to do count for each row from table but I get this error:

Can not perform an aggregate function on an expression containing an aggregate or a subquery.

   SELECT     TOP (100) PERCENT ISNULL(MAX(Id), 0) AS ID, 
           MONTH(p.datep) AS nMonth, 
           DATENAME(mm, p.dateP) AS month, 
           YEAR(p.dateP) AS year, c.EId, e.SId,
           e.nE, s.libelle,
           SUM(p.a) AS a, 
           SUM(p.a - p.b) AS c, 
           SUM(p.b) AS b, 
           SUM(p.dureePM + p.dureeAM) AS dX,
           SUM(CASE WHEN p.dureePm != 0 THEN 1 ELSE 0 END) AS nbrPm, 
           SUM(CASE WHEN p.dureeAm != 0 THEN 1 ELSE 0 END) AS nbrAm, 
           COUNT(CASE WHEN p.nbX > 2 THEN  SUM(p.nbX-2)  ELSE 0 END) AS nbrXSupp, 
           COUNT(CASE WHEN p.nbY > 2 THEN  SUM(p.nbY-2)  ELSE 0 END) AS nbrYSupp

FROM       dbo.table AS p 
INNER JOIN
           dbo.tableC AS c ON p.cId = c.CId 
INNER JOIN
           dbo.tableE AS e ON c.EId = e.EId 
INNER JOIN
            dbo.tableS AS s ON e.SId = s.SId

GROUP BY MONTH(p.dateP), DATENAME(mm, p.dateP), YEAR(p.dateP), 
          c.EId, e.SId, e.nE, s.libelle

Answer 1

The easiest way is to use a CTE. Hope this help

CREATE TABLE ##tableA (id INT, x INT, y INT) INSERT INTO ##tableA VALUES (1, 5, 3), (2, 7, 2), (3, 2, 5)

;WITH SUMS AS( SELECT id,
CASE WHEN x> 2 THEN (x-2) ELSE 0 END AS number1, CASE WHEN y > 2 THEN (y-2) ELSE 0 END AS number2

FROM ##tableA )

SELECT * FROM SUMS

Answer 2

Select SUM(T1Count.TotalRec) T1Counts, SUM(T2Count.TotalRec) T2Counts 
From Table1 T01 
Outer Apply (Select COUNT(T01_Id) TotalRec From Table1 T1 Where T1.T01_Id=T01.T01_Id And T01_FieldToCheck > 1) T1Count
Outer Apply (Select COUNT(T01_Id) TotalRec From Table1 T1 Where T1.T01_Id=T01.T01_Id And T01_FieldToCheck =< 1) T2Count

I think this would help you a little to sort out your problem. This way you can have different conditional summary on your data.

get back if any problem in the same.

Answer 3

Below query will give the required output :-

SELECT id,
CASE WHEN min(x)> 2  THEN  (min(x)-2) ELSE 0  END AS number1, 
CASE WHEN min(y) > 2 THEN (min(y)-2)  ELSE 0 END AS number2
FROM tableA
group by id

Output :-

id  number1 number2
 1     3    1
 2     5    0
 3     0    3

Answer 4

As already mentioned in my comment, SQl server doesn't support aggregate function inside another. you can achieve you purpose by breaking your query in two steps. I have kept your query in a cte and further queried it to get count on the columns you needed.

 with cte as
(
 SELECT     TOP (100) PERCENT ISNULL(MAX(Id), 0) AS ID, 
           MONTH(p.datep) AS nMonth, 
           DATENAME(mm, p.dateP) AS month, 
           YEAR(p.dateP) AS year, c.EId, e.SId,
           e.nE, s.libelle,
           SUM(p.a) AS a, 
           SUM(p.a - p.b) AS c, 
           SUM(p.b) AS b, 
           SUM(p.dureePM + p.dureeAM) AS dX,
           SUM(CASE WHEN p.dureePm != 0 THEN 1 ELSE 0 END) AS nbrPm, 
           SUM(CASE WHEN p.dureeAm != 0 THEN 1 ELSE 0 END) AS nbrAm, 
           CASE WHEN p.nbX > 2 THEN  SUM(p.nbX-2)  ELSE 0 END AS nbrXSupp, --removed the COUNT
           CASE WHEN p.nbY > 2 THEN  SUM(p.nbY-2)  ELSE 0 END AS nbrYSupp

FROM       dbo.table AS p 
INNER JOIN
           dbo.tableC AS c ON p.cId = c.CId 
INNER JOIN
           dbo.tableE AS e ON c.EId = e.EId 
INNER JOIN
            dbo.tableS AS s ON e.SId = s.SId

GROUP BY MONTH(p.dateP), DATENAME(mm, p.dateP), YEAR(p.dateP), 
          c.EId, e.SId, e.nE, s.libelle
)
select cte.*,count(nbrXSupp) as Cn_nbrXSupp,count(nbrYSupp) as Cn_nbrYSupp
from cte
group by nMonth,month,year,EId,SId, nE,libelle

Hope it helps. Obviously I haven't run and tested it.If there are any column binding issues in the query, please sort them out.