在case sql語句中使用sum和count

Question

我想對表中的每一行進行計數，但是我收到此錯誤：

無法對包含聚合或子查詢的表達式執行聚合函數。

   SELECT     TOP (100) PERCENT ISNULL(MAX(Id), 0) AS ID, 
           MONTH(p.datep) AS nMonth, 
           DATENAME(mm, p.dateP) AS month, 
           YEAR(p.dateP) AS year, c.EId, e.SId,
           e.nE, s.libelle,
           SUM(p.a) AS a, 
           SUM(p.a - p.b) AS c, 
           SUM(p.b) AS b, 
           SUM(p.dureePM + p.dureeAM) AS dX,
           SUM(CASE WHEN p.dureePm != 0 THEN 1 ELSE 0 END) AS nbrPm, 
           SUM(CASE WHEN p.dureeAm != 0 THEN 1 ELSE 0 END) AS nbrAm, 
           COUNT(CASE WHEN p.nbX > 2 THEN  SUM(p.nbX-2)  ELSE 0 END) AS nbrXSupp, 
           COUNT(CASE WHEN p.nbY > 2 THEN  SUM(p.nbY-2)  ELSE 0 END) AS nbrYSupp

FROM       dbo.table AS p 
INNER JOIN
           dbo.tableC AS c ON p.cId = c.CId 
INNER JOIN
           dbo.tableE AS e ON c.EId = e.EId 
INNER JOIN
            dbo.tableS AS s ON e.SId = s.SId

GROUP BY MONTH(p.dateP), DATENAME(mm, p.dateP), YEAR(p.dateP), 
          c.EId, e.SId, e.nE, s.libelle

Answer 1

最簡單的方法是使用CTE。 希望這有幫助

CREATE TABLE ## tableA（id INT，x INT，y INT）INSERT INTO ## tableA VALUES（1,5,3），（2,7,2），（3,2,5）

; WITH SUMS AS（SELECT id，
情況x> 2 THEN（x-2）ELSE 0 END作為number1，情況y> 2 THEN（y-2）ELSE 0 END AS number2

來自## tableA）

SELECT * FROM SUMS

Answer 2

Select SUM(T1Count.TotalRec) T1Counts, SUM(T2Count.TotalRec) T2Counts 
From Table1 T01 
Outer Apply (Select COUNT(T01_Id) TotalRec From Table1 T1 Where T1.T01_Id=T01.T01_Id And T01_FieldToCheck > 1) T1Count
Outer Apply (Select COUNT(T01_Id) TotalRec From Table1 T1 Where T1.T01_Id=T01.T01_Id And T01_FieldToCheck =< 1) T2Count

我認為這可以幫助你解決一些問題。 這樣，您可以對數據進行不同的條件摘要。

如果有任何問題，請回來。

Answer 3

下面的查詢將給出所需的輸出： -

SELECT id,
CASE WHEN min(x)> 2  THEN  (min(x)-2) ELSE 0  END AS number1, 
CASE WHEN min(y) > 2 THEN (min(y)-2)  ELSE 0 END AS number2
FROM tableA
group by id

輸出： -

id  number1 number2
 1     3    1
 2     5    0
 3     0    3

Answer 4

正如我在評論中已經提到的，SQl服務器不支持另一個內部的聚合函數。 您可以通過兩個步驟打破查詢來實現目的。 我已將您的查詢保存在cte中，並進一步查詢它以計算您需要的列。

 with cte as
(
 SELECT     TOP (100) PERCENT ISNULL(MAX(Id), 0) AS ID, 
           MONTH(p.datep) AS nMonth, 
           DATENAME(mm, p.dateP) AS month, 
           YEAR(p.dateP) AS year, c.EId, e.SId,
           e.nE, s.libelle,
           SUM(p.a) AS a, 
           SUM(p.a - p.b) AS c, 
           SUM(p.b) AS b, 
           SUM(p.dureePM + p.dureeAM) AS dX,
           SUM(CASE WHEN p.dureePm != 0 THEN 1 ELSE 0 END) AS nbrPm, 
           SUM(CASE WHEN p.dureeAm != 0 THEN 1 ELSE 0 END) AS nbrAm, 
           CASE WHEN p.nbX > 2 THEN  SUM(p.nbX-2)  ELSE 0 END AS nbrXSupp, --removed the COUNT
           CASE WHEN p.nbY > 2 THEN  SUM(p.nbY-2)  ELSE 0 END AS nbrYSupp

FROM       dbo.table AS p 
INNER JOIN
           dbo.tableC AS c ON p.cId = c.CId 
INNER JOIN
           dbo.tableE AS e ON c.EId = e.EId 
INNER JOIN
            dbo.tableS AS s ON e.SId = s.SId

GROUP BY MONTH(p.dateP), DATENAME(mm, p.dateP), YEAR(p.dateP), 
          c.EId, e.SId, e.nE, s.libelle
)
select cte.*,count(nbrXSupp) as Cn_nbrXSupp,count(nbrYSupp) as Cn_nbrYSupp
from cte
group by nMonth,month,year,EId,SId, nE,libelle

希望能幫助到你。 顯然我沒有運行並測試它。如果查詢中有任何列綁定問題，請將它們排序。