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如何取消除数组中的一个索引之外的其余元素

[英]How to unset rest of element except then one index in array

Have an array i want to unset rest of element except then one index in array 有一个我想取消设置其余元素的数组,但数组中只有一个索引

Array 数组

$array = Array ( "Result" => Array ( "ResponseStatus" => 1, "Hotels" => Array ( Array ( "Rating" => 1, "Description" => "Description1" ), Array ( "Rating" => 2, "Description" => "Description2"), Array ( "Rating" => 4, "Description" => "Description3") ) ) );

Like i want keep only $array['Result']['Hotels'][1] and unset rest of index 就像我只想保留$ array ['Result'] ['Hotels'] [1]并保留其余索引

Want Output 想要输出

Array
(
    [Result] => Array
        (
            [ResponseStatus] => 1
            [Hotels] => Array
                (
                    [1] => Array
                        (
                            [Rating] => 2
                            [Description] => Description2
                        )
                )
        )
)

I have tried this 我已经试过了

$arrayKey = 1;
foreach ($array['Result']['Hotels'] as $key => &$value) {
    if (!$key == $arrayKey) {
        unset($value[$key]);
    }
}

我只是将所需的元素从数组中复制出来,而忘记了原始数组。

$arrayKey = 1;
foreach ($array['Result']['Hotels'] as $key => &$value) {

    if ($key != $arrayKey) {
        unset($value[$key]);
    }

}

You can use array_intersect_key function creating an array with the desired key (keys). 您可以使用array_intersect_key函数创建具有所需键(键)的数组。 In this case [1=>null] ; 在这种情况下[1=>null] ;

$array['Result']['Hotels'] = array_intersect_key($array['Result']['Hotels'], [1=>null]);

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