如何取消除數組中的一個索引之外的其余元素

Question

有一個我想取消設置其余元素的數組，但數組中只有一個索引

數組

$array = Array ( "Result" => Array ( "ResponseStatus" => 1, "Hotels" => Array ( Array ( "Rating" => 1, "Description" => "Description1" ), Array ( "Rating" => 2, "Description" => "Description2"), Array ( "Rating" => 4, "Description" => "Description3") ) ) );

就像我只想保留$ array ['Result'] ['Hotels'] [1]並保留其余索引

想要輸出

Array
(
    [Result] => Array
        (
            [ResponseStatus] => 1
            [Hotels] => Array
                (
                    [1] => Array
                        (
                            [Rating] => 2
                            [Description] => Description2
                        )
                )
        )
)

我已經試過了

$arrayKey = 1;
foreach ($array['Result']['Hotels'] as $key => &$value) {
    if (!$key == $arrayKey) {
        unset($value[$key]);
    }
}

Answer 1

我只是將所需的元素從數組中復制出來，而忘記了原始數組。

Answer 2

$arrayKey = 1;
foreach ($array['Result']['Hotels'] as $key => &$value) {

    if ($key != $arrayKey) {
        unset($value[$key]);
    }

}

Answer 3

您可以使用array_intersect_key函數創建具有所需鍵（鍵）的數組。 在這種情況下[1=>null] ;

$array['Result']['Hotels'] = array_intersect_key($array['Result']['Hotels'], [1=>null]);