如何确保用户在python 3.5.1中的Guess游戏中输入正确的输入？

Question

This is my code:

from random import randint
print("What is your name?")
name=input()
tries=0
number= randint(1,100)
print("Hello, %s guess a number from 0 to 100" % name)
while tries < 8:
    print("Take a Guess")
    guess=input()
    guess=int(guess)
    if guess < number:
        print("Too Low")
        tries += 1
    if guess > number:
        print("Too High")
        tries += 1
    if guess == number:
        break

if guess == number:
   print("You got it, in %s tries" % tries)

if guess != number:
    print("Sorry try again!")

But it gives an error:

Traceback (most recent call last):
  File "/Users/Zuazua/PycharmProjects/untitled/GuessMyNumber2.py", line 10, in <module>
    guess=int(guess)
ValueError: invalid literal for int() with base 10: '23!'

Answer 1

将行guess=int(guess)更改为此：

guess=int(re.search(r'\d+', guess).group())

Answer 2

Attempt to parse entered value with guess=int(guess) can lead to different exceptions. Quick and dirty way to fix it - is to wrap it in try ... except block. Like:

try:
    guess=int(guess)
except ValueError:
    print("Cannot understand your input. Pls, try again")
    continue

This code will catch all ValueError exceptions occured during parsing. You may find here more info on exceptions: https://docs.python.org/3/tutorial/errors.html#errors-and-exceptions