如何確保用戶在python 3.5.1中的Guess游戲中輸入正確的輸入？

Question

這是我的代碼：

from random import randint
print("What is your name?")
name=input()
tries=0
number= randint(1,100)
print("Hello, %s guess a number from 0 to 100" % name)
while tries < 8:
    print("Take a Guess")
    guess=input()
    guess=int(guess)
    if guess < number:
        print("Too Low")
        tries += 1
    if guess > number:
        print("Too High")
        tries += 1
    if guess == number:
        break

if guess == number:
   print("You got it, in %s tries" % tries)

if guess != number:
    print("Sorry try again!")

但是它給出了一個錯誤：

Traceback (most recent call last):
  File "/Users/Zuazua/PycharmProjects/untitled/GuessMyNumber2.py", line 10, in <module>
    guess=int(guess)
ValueError: invalid literal for int() with base 10: '23!'

Answer 1

將行guess=int(guess)更改為此：

guess=int(re.search(r'\d+', guess).group())

Answer 2

嘗試使用guess=int(guess)解析輸入的值可能導致不同的異常。 修復它的快速而又骯臟的方法-將其包裝在try ... except塊。 喜歡：

try:
    guess=int(guess)
except ValueError:
    print("Cannot understand your input. Pls, try again")
    continue

此代碼將捕獲在解析期間發生的所有ValueError異常。 您可以在此處找到有關異常的更多信息： https : //docs.python.org/3/tutorial/errors.html#errors-and-exceptions