使用带有python的正则表达式来查找唯一的数字格式

Question

I have a very large text file (45000 lines) with ID #'s in the format of 4 or 5 numbers followed by 2 or 3 numbers and then a letter sometimes trailing at the end.

Sample example formats:

XXXX-XX XXXXX-XX ,XXXXX-XXw, XXXXX-XXw, XXXXX-XXww

((Where w is a letter and X is a number))

Most of the values are in the format of #####-## or ####-##, but a large chunk have 1 or more letter trailing at the end.

What I want to do: Whenever there is a value that has a letter at the end I want to store it in a dictionary and keep track of all the unique values of letters that diverge from the normal format, and then print that dictionary.

So for values like: 11111-12s or 1111-12a or 11234-24b I want to store the letter values (s, a , b) and see the differences. What I have currently just displays the values and also repeats:

import re

sampleFile = open("Sample.txt", "r")

#regEX formats
sample = re.compile(r'(\d{4,5}-\d\d\w{1,4})')

for line in sampleFile:
    sampleNum = sample.findall(line)
    for word in sampleNum:
        print word

How would I go about doing this targeting unique values of the w{1,4} portion of the regex and storing them in a dict?

EDIT:When I run above this is a sample of numbers I get:

12647-01a 12627-02R 12606-01a 12588-02a 12583-01S 12583-01R

So those values at the end vary, and I just want to store the end letter (sometimes there is 2 or more) in a dict or set. Hope this helps

Answer 1

A simple set which reads your regex should match your clarified comment:

import re
uniq = set()
with open('Sample.txt') as fin:
    for line in fin:
        ma = re.search(r'(\w{1,4})$', line)
        if not ma:
            continue
        uniq.add(ma.group(1))

print(uniq)