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在单个查询中将结果作为单个数组获取

[英]Fetch result as single array in single query

I need to join tables and fetch output as single array in single query, even though a user has multiple address 我需要连接表并在单个查询中将输出作为单个数组获取,即使用户有多个地址

My query: 我的查询:

SELECT user.name, address.address, user.place 
FROM user 
LEFT JOIN address 
WHERE user.user_id = address.user_id 
GROUP BY user.name, address.address, user.place

Suppose a user has multiple address am currently getting output as two rows.Is there any way to collect all output values in a single array using single query. 假设一个用户有多个地址当前正在作为两行输出,是否有任何方法可以使用单个查询将所有输出值收集到单个数组中。

Please help. 请帮忙。

You can use group_concat in your query. 您可以在查询中使用group_concat

SELECT user.name, group_concat(address.address) as 'address', user.place 
FROM user 
LEFT JOIN address 
WHERE user.user_id = address.user_id

Another way is to use FOR XML statement: 另一种方法是使用FOR XML语句:

SELECT DISTINCT 
            u.name, 
            STUFF((SELECT ';' + a.[address]
            FROM address a
            WHERE u.[user_id] = a.[user_id]
            FOR XML PATH('')),1,1,'') as [address],
            u.place
FROM [user] u

Output will be like: 输出将如下所示:

name    address         place
Mike    adr1;adr2;adr3  someplace

Try FOR XML PATH('') , it will join you addresses in one row: 尝试FOR XML PATH('') ,它将把您的地址加入一行:

select
    [user].[name],
    (select [address] + ', '
    from [address]
    where
        [user_id] = [user].[user_id]
    for xml path('')),
    user.place
from [user]

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