[英]Fetch result as single array in single query
I need to join tables and fetch output as single array in single query, even though a user has multiple address 我需要连接表并在单个查询中将输出作为单个数组获取,即使用户有多个地址
My query: 我的查询:
SELECT user.name, address.address, user.place
FROM user
LEFT JOIN address
WHERE user.user_id = address.user_id
GROUP BY user.name, address.address, user.place
Suppose a user has multiple address am currently getting output as two rows.Is there any way to collect all output values in a single array using single query. 假设一个用户有多个地址当前正在作为两行输出,是否有任何方法可以使用单个查询将所有输出值收集到单个数组中。
Please help. 请帮忙。
You can use group_concat
in your query. 您可以在查询中使用
group_concat
。
SELECT user.name, group_concat(address.address) as 'address', user.place
FROM user
LEFT JOIN address
WHERE user.user_id = address.user_id
Another way is to use FOR XML statement: 另一种方法是使用FOR XML语句:
SELECT DISTINCT
u.name,
STUFF((SELECT ';' + a.[address]
FROM address a
WHERE u.[user_id] = a.[user_id]
FOR XML PATH('')),1,1,'') as [address],
u.place
FROM [user] u
Output will be like: 输出将如下所示:
name address place
Mike adr1;adr2;adr3 someplace
Try FOR XML PATH('') , it will join you addresses in one row: 尝试FOR XML PATH('') ,它将把您的地址加入一行:
select
[user].[name],
(select [address] + ', '
from [address]
where
[user_id] = [user].[user_id]
for xml path('')),
user.place
from [user]
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