单个数组中的多个mysql查询结果

Question

how can i add result of multiple queries in a single array so it makes it easier to later output.

for example,

$newArray = array("mike", "john");
while ($newArray !== false){
    $sql = "Select * from accounts where name = '$newArray'";
    $result = mysqli_query($db_connection,$sql);
}

 while ($row = mysqli_fetch_assoc($result)) {
    printf $row['firstName'];
    echo "----";
    printf $row['num_accounts'];
    echo "----";
    prinf $row['location'];
    echo "----";
    echo "<br>";
}

i am sure i am missing something that obvious. but the idea is that i want to setup a loop to read from an array and then execute the query and store the results. each time query executes the condition is different but from same table, , but then keep adding the results to single output, making it easier to output in the end.

Answer 1

you could avoid the while simple using in clause based on list of values you need

$newList = "'mike', 'john'";

$sql = "Select * from accounts where name IN (" .$newList .")";

but you should not use php var in sql ..you are at risk for sqlinjection .. for avoid this you should take a look at your sqldruver for binding param ..

but if you want append the result for different where condition on same table you should take a look at UNION clause

$sql = "Select * from accounts where name IN (" .$newList .") 
        UNION 
        Select * from accounts  where you_col > 10";

Answer 2

There's a few things wrong with your code..
1. You are inputting a full array into your query.
2. You're doing no preparations on your query thus it's vulnerable to sql injection if $newArray is human input data.
3. Your logic from looping thru the data, if you managed to get a single query correct, would always loop thru the last query. You need to move the $row = mysqli_fetch_assoc($result) stuff inside your actual loop.

To get this code working it would look like so:

$newArray = array("mike", "john");
foreach($newArray as $name){
    $sql = "Select * from accounts where name = '{$name}'";
    $result = mysqli_query($db_connection,$sql);

    while ($row = mysqli_fetch_assoc($result)) {
        printf $row['firstName'];
        echo "----";
        printf $row['num_accounts'];
        echo "----";
        prinf $row['location'];
        echo "----";
        echo "<br>";
    }
}