从日期中提取年份，并使用年份从数据库中获取数据

Question

First of all i'd like to say that i am fairly new to the programming world. I am creating a system where Date plays a major role, I am currently able to display all the items where full date is shown, however i would like to create a menu where the user can view his transactions by month and year.

    echo "<table border='1'>";
    echo "<tr><th>Transaction Date</th><th>Total Amount</th></tr>"; 

    $val=mysqli_query($conn,"SELECT TransactionDate, SUM(Amount) FROM                   transaction GROUP BY TransactionDate");
    while($row = mysqli_fetch_array($val))
    { 
        echo ("

        <tr><td><a href='inserttransaction.php?date=$row[0]'>$row[0]</a></td>
        <td>$row[1]</td></tr>");

    }

With the help of the above code i was able to group them all by using the current date, I'm quite new to the programming world and need help or clues on how do i make it year wise or say month wise. How am i supposed to extract only the "year" from it and as i am gonna go and display all the items saved in the DB with the current YEAR, how do i extract those items through the DB?

Answer 1

You can use mysql DATE_FORMAT

Something like for yearly grouping:

SELECT DATE_FORMAT(TransactionDate, "%Y") as date_key, 
       SUM(Amount) 
 FROM transaction 
GROUP BY date_key;

Answer 2

Try some thing like this.first fetch the date from db and move it to variable.To know the date format Manual click here

$datz=$row['date'];
$time=strtotime($dateValue);
$month=date("F",$time);
$year=date("Y",$time);