更新迭代中的每一行-逻辑结构辅助

Question

I need assitance to figure out this problem. I tried to simplify thing as possible. There aren't any errors, it's just a matter of accessing that I can't afford to figure out.

Imagine :

<?php
   for($i=0;$i<3;$i++){
   ?>
    Member:
    <input type="text" name="<?php echo trim("member_".$i);?>" />
    <br/>
   <?php
   } ?>

The above codes generates :

<input name="member_1">
 <input name="member_2">
 <input name="member_3">

and now assuming, the data in table

org_ID (Foreign Key)    member
A                          1
A                          2
A                          3

Now come to update function :

public function updateTo($tableName, $org_D,$member) {
        try {
            $stm = "update " . $tableName . " SET member = :member WHERE org_D= :org_D";
            $eksekutor = $this->koneksi->prepare($stm);
            $eksekutor->bindValue(":org_D",  $org_D, PDO::PARAM_STR);
            $eksekutor->bindValue(":member ", $member, PDO::PARAM_STR);
             $eksekutor->execute();
            $done = true;
        } catch (PDOException $e) {
            $done = false;
        }
        return $done;
    }

and finally the update operation :

If I do this ( which is wrong since it keeps updating all row for each iteration ):

for($i=0;$i<3;$i++) {
    $member = $_POST["member_$i"];
    $update = $kad->updateTo("table_name", $org_D,  $member);
}

I need help, I can't afford to figure out how to achive this update operation:

$_POST["member_1"]; ------ UPDATE TO-------> row "member" contains 1
$_POST["member_2"]; ------ UPDATE TO-------> row "member" contains 2
$_POST["member_3"]; ------ UPDATE TO-------> row "member" contains 3

since in update operation I've to decide value for each WHERE=

Answer 1

Currently your sending the same UPDATE statement to you database in each iteration. If you want to update a single member per iteration you'll have to add that to your WHERE clause.

Maybe you have something more to reference a member than given in your example. Otherwise you'll have to add the previous member-value to your where clause.

public function updateTo($tableName, $org_D, $prevMember, $newMember) {
    ...
    $stm = "update " . $tableName . " SET member= :newMember WHERE org_D=:org_D AND member = :prevMember";
    $eksekutor = $this->koneksi->prepare($stm);
    $eksekutor->bindValue(":org_D",  $org_D, PDO::PARAM_STR);
    $eksekutor->bindValue(":newMember", $newMember, PDO::PARAM_STR);
    $eksekutor->bindValue(":prevMember", $prevMember, PDO::PARAM_STR);
    ...
}

Answer 2

The problem is because of your WHERE condition. See here,

...WHERE org_D= :org_D";

Since you're passing A , your org_D , as an argument to the method, it's updating all three rows in each iteration of for loop. You need to pass the current member's id to the updateTo() method as well.

So, first change your for loop in the following fashion,

for($i=0;$i<3;$i++) {
    $member = $_POST["member_$i"];
    $update = $kad->updateTo("table_name", $i+1, $org_D,  $member);
}

And then change the updateTo() method in the following way,

public function updateTo($tableName, $oldMemberId, $org_D, $newMemberId) {
    try {
        $stm = "update " . $tableName . " SET member = :newMemberId WHERE member = :oldMemberId AND org_D= :org_D";
        $eksekutor = $this->koneksi->prepare($stm);
        $eksekutor->bindValue(":newMemberId ", $newMemberId, PDO::PARAM_STR);
        $eksekutor->bindValue(":oldMemberId ", $oldMemberId, PDO::PARAM_STR);
        $eksekutor->bindValue(":org_D",  $org_D, PDO::PARAM_STR);
        $eksekutor->execute();
        $done = true;
    } catch (PDOException $e) {
        $done = false;
    }
    return $done;
}