将快速委托转换为标准函数

Question

i'm trying to convert FastDelegate into a std::function, but am having trouble understanding the syntax.

this is the delegate library: http://www.codeproject.com/Articles/7150/Member-Function-Pointers-and-the-Fastest-Possible

and the code i'm trying to convert:

typedef shared_ptr<IEventData> IEventDataPtr;  
typedef fastdelegate::FastDelegate1<IEventDataPtr> EventListenerDelegate;

//some code to find the event

EventListenerDelegate listener = (*it);  
listener(pEvent); // call the delegate

So far this can't work:

typedef std::function<std::shared_ptr<IEventData>> Functor;
Functor listener = (*it);
listener(pEvent); // call the delegate

Answer 1

This may not be a complete answer as I'm not entirely sure what the fastDelegate library is support to do other than offer the callback functionality. The original code there comes from Game Coding Complete by Mike Shaffry & Dave Graham.

So I may be missing the part where the books says the fastDelegate Library can attach member variables. So since you have a void function with IEventData as a parameter, all your callback functions will be the same.

    typedef std::function<void(IEventData)> Functor;
    Functor listener = (*it);
    listener(pEvent);

Then defined somewhere else in your solution would be the actualy "Functor" which is just a typedef for std::function. Such as:

   void GameCode::DelegateFunction(IEventData){
   //do stuff with event
   }

That's pretty much the gist of how it works. I know this post is old but I figured I'd answer anyways since I was just figuring it out at 4 am myself