[英]Python 3.X jumping to a line of code
I'm trying to make a Choose Your Own Adventure game in Python 3.X. 我正在尝试使用Python 3.X创建一个“选择自己的冒险”游戏。 I'm using the idle platform.
我正在使用空闲平台。 Here is a sample of my code.
这是我的代码示例。
import time
again = True
while again == True:
print("You wake up as you normally do, but something's not quite right. What will be the first thing you do? \n Choices: \n Go back to sleep \n Get up")
action1 = input(": ")
if action1 == "Go back to sleep":
print("You lazyhead. As you were about to fall asleep, your ceiling collapsed on you and killed you. Don't be lazy.")
playAgain = input("Play again? Y/N: ")
if playAgain == "Y":
again = True
elif playAgain == "N":
again = False
Obviously, there is stuff between action1
and playAgain
. 显然,在
action1
和playAgain
之间有东西。 I want to replace again = false
in elif playAgain =="N"
我想在
elif playAgain =="N"
again = false
替换again = false
elif playAgain =="N":
again = false
I want to instead jump to playAgain
so I don't just end the program. 我想跳
playAgain
再次playAgain
所以我不只是结束程序。 This is my first question so my formatting is probably a bit weird so please correct that too. 这是我的第一个问题,因此我的格式可能有点怪异,因此也请更正。
As mentioned, python doesn't support GoTo
. 如前所述,python不支持
GoTo
。 One way of achieving the same result is to create a quit game function like below then call it at the end of your main game code. 实现相同结果的一种方法是创建一个退出游戏函数,如下所示,然后在主游戏代码的末尾调用它。
def quit_game():
playAgain = input("Play again? Y/N: ")
if playAgain == "Y":
return True
elif playAgain == "N":
quit_game()
In original code: 用原始代码:
...
again = quit_game()
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