python 3.x覆盖前一个终端行

Question

I wrote a simple program to calculate average outcome of a dice throw (pretty pointless, but you have to start somewhere ;P):

import random, time
from random import randrange

count = 0
total = 0
one_count = 0 

for x in range(10000000):
    random = randrange(1,7)
    count = count + 1
    total = total + random
    average = total / count
    percentage = one_count / count * 100
    if random == 1:
        one_count = one_count + 1
    print("the percentage of ones occurring is", percentage, "and the average outcome is", average)
#   time.sleep(1)

To clean it up I want the output to overwrite the previous line. I tried everything I could find, but the only thing I managed to to is to print to the same line without erasing the previous content by changing the last line to:

print("the percentage of ones occuring is", percentage, "and the average outcome is", average, "/// ", end="")

which outputs:

the percentage of ones occuring is 0.0 and the average outcome is 4.0 /// the percentage of ones occuring is 0.0 and the average outcome is 4.5 /// the percentage of ones occuring is 0.0 and the average outcome is 3.6666666666666665 /// 

Any ideas?

Answer 1

Add a \\r at the end. That way, the next line you write will start at the beginning of the previous line. And then flush output so it shows immediately.

Note: If the next line is shorter, the remaining characters will still be there.

Answer 2

use end='\\r :

for x in range(100000):
    rnd = randrange(1,7) # don't use random
    count += 1
    total = total + rnd
    average = total / count
    percentage = one_count / count * 100
    if rnd == 1:
        one_count += 1
    print("the percentage of ones occurring is {} and the average outcome is {}".format(percentage,average),end='\r')
    time.sleep(.1)

On another note using total = total + random is not a good idea, you are importing the random module and using random as a variable name.