正则表达式匹配除模式以外的所有内容

Question

I am coming from this question . Now what I want is the exact opposite. I want to match all chracters except this pattern:

yearid="[0-9]+"

Why do I do that please?

I have tried (?!yearid="[0-9]+") but it refuses to match match.

Answer 1

There are actually two ways to do this. You can use [^0-9]+ where the ^ negates the term inside the brackets, or \\D+ where \\D is any non-digit character.

Answer 2

re.sub(r'yearid="[0-9]+"', '', string_to_fix)

Capture the group like normal, then substitute nothing for it, and return the complete string.

Or, if you want to go the hard way and negate it:

re.sub(r'(.*?)(?:yearid="[0-9]+")(.*)', '\\1\\2', string_to_fix)

This first matches everything lazily (.*?) , until it finds the yearid="XXXX" , matches that as a noncapturing group (?:yearid="[0-9]+") , then matches everything else (.*) . Finally, it replaces the original full string with just the 1st and 2nd capture groups, essentially cutting out the section you want.