[英]Regex match everything between two {}
I was looking at different answers here but unfortunately none of them was good for my case. 我在这里看到了不同的答案,但不幸的是,这些答案都不适合我的情况。 So I hope you don't mind about it. 所以我希望你不介意。
So I need to match everything between two curly brackets {} except situation when match starts with @ and without these curly brackets eg: 所以我需要匹配两个大括号{}之间的所有内容,除了匹配以@开头且没有这些大括号的情况,例如:
Here are my test strings, 1,2,3 are valid while the last one shouldn't be: 这是我的测试字符串,1,2,3有效,而最后一个不应该是:
1 {eww}
2 r23r23{fetwe}
3 #{d2dded}
4 @{d2dded}
I was trying with: 我正在尝试:
(?<=[^@]\{)[^\}]*(?=\})
Then only 2th and 3th options were matches (without the first one) https://regex101.com/r/qRInUf/2/ 然后只有第2和第3个选项匹配(没有第一个) https://regex101.com/r/qRInUf/2/
Then I was trying: 然后我在尝试:
\{(.*?)\} or [^@]\{(.*?)\}
In both cases I was unable to match 1,2,3 values https://regex101.com/r/uYRtLD/1 在这两种情况下,我都无法匹配1,2,3值https://regex101.com/r/uYRtLD/1
Thanks in advance for any suggestions. 在此先感谢您的任何建议。
EDIT: This is for java. 编辑:这是为java。
See regex in use here 请参阅此处使用的正则表达式
(?<=(?<!@)\{)[^}]*(?=})
(?<=(?<!@)\\{)
Positive lookbehind ensuring what precedes matches the following (?<=(?<!@)\\{)
正向后视确保先于匹配以下内容的内容
(?<!@)
Negative lookbehind ensuring what precedes doesn't match @
literally (?<!@)
负回顾后保证什么先不匹配@
字面上 \\{
Match {
literally. \\{
匹配{
字面意思。 [^}]*
Matches any character except }
any number of times [^}]*
匹配除}
以外的任何字符 (?=})
Positive lookahead ensuring what follows is }
literally (?=})
正前瞻确保接下来是}
字面上 Results: 结果:
{eww} # Matches eww
r23r23{fetwe} # Matches fetwe
#{d2dded} # Matches d2dded
@{d2dded} # Does not match this because @ precedes {
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