在不使用iOS应用程序中的任何特定URL的情况下启动Safari App

Question

In one of my iOS App, I have to just launch the Safari App and not open some specific Url in Safari which can be achieved by this:

NSURL *url = [NSURL URLWithString:@"http://www.stackoverflow.com"];

if (![[UIApplication sharedApplication] openURL:url]) {
NSLog(@"%@%@",@"Failed to open url:",[url description]);
}

But I only need to launch safari App with last tab open (in the same state that I leave before entering that iOS App).

Any suggestion and help will be welcome. Thanks!

Answer 1

Actually we can open a specific app from safari. You have to create a custom url scheme for the application and open that link from safari like any other link is opened from safari.

Create a custom url scheme like

myApp://

Then open it from safari eg on onClick of button.

Answer 2

Objective C

NSURL *url = [NSURL URLWithString:@"http://about:blank"];
if (![[UIApplication sharedApplication] openURL:url]) {
    NSLog(@"%@%@",@"Failed to open url:",[url description]);
}  

Swift 3.0

UIApplication.shared().openURL(URL(string: "http://about:blank")!)

Hope It will help you.

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