如何在python中将二进制和ascii的组合转换为人类可读的格式

Question

Below is my code for receiving data over socket.

from twisted.internet.protocol import Factory
from twisted.protocols.basic import LineReceiver
from twisted.internet import reactor

class Chat(LineReceiver):

    def lineReceived(self, line):
        print(line)

class ChatFactory(Factory):

   def __init__(self):
       self.users = {} # maps user names to Chat instances

   def buildProtocol(self, addr):
       return Chat()

reactor.listenTCP(9600,ChatFactory())
reactor.run()

I got response from the client with

b'$$\x00pP$\x91\x97\x01\xff\xff\x99\x99P000002.000,V,0000.0000,N,00000.0000,E,0.00,000.00,060180,,*09|||0000|0000,0000|000000113|00000[\x86'

which is combination of hex code and ascii, the location information is in ascii format. What is the best way to convert this data into human readable format?

I need to parse header, L and ID .

<$$><L><ID><command><data><checksum><\r\n>

• header = 2 bytes and it will be in hex code representation of 0x24
• L = 2 bytes and it is in the format of hex code .
• ID = 7 bytes and it is in the format of hex code .
• command = 2 bytes, it will be in hex code
• data will be in ascii format.
• checksum = 2 bytes and in hex code

Thanks in advance.

Answer 1

This can be solved just with the binary string:

import struct
header = line[:2]
if header!=b'$$':
    raise RuntimeError('Wrong header')
# Assumes you want two have 2 bytes, not one word
L = struct.unpack('BB',line[2:4])
ID = struct.unpack('7B', line[4:11])
location = line[11:]
print 'L={},{}, ID={}, location={}'.format(L[1],L[2], ''.join(str(b) for b in ID, location)

The link to struct is in the other answer

Answer 2

You can use struct.unpack() , but you have to know what you are gonna unpack (int, long, signed, etc.), the endiness if it is encoded on more that 1 bytes, ASCII are 7 bits, encoded on 1 byte.

Read more about struct here .