从字典中筛选出密钥

Question

Having dictionary (defined in map.jinja )

{% set intellij = salt['grains.filter_by']({
    'default': {
        'orig_name': 'idea-IC-145.1617.8',
        'download_url': 'www.example.com',         
        'archive_format': 'tar',
        'archive_opts': 'xfz',
        'owner': 'root',
        'owner_link_location': '/blabla/bin/idea',
    },
}, merge=salt['pillar.get']('intellij')) %}

and some function definition accepting arguments almost the same as the dictionary's keys (let's assume the "function" is actually a macro)

{% macro some_macro(state_id, orig_name, download_url, archive_format, owner, archive_opts=None) %}

I would like to filter out some keys so that I can call it like this:

{{ some_macro('some_state', **intellij) }}

I've tried various constructs, like:

{{ some_macro('intellij', **(intellij|rejectattr("owner_link_location"))) }}

which yields

Jinja error: call() argument after ** must be a mapping, not generator

Dict-comprehension (instead of jinja filter) also doesn't work.

How to achieve the aforementioned functionality (filtering out the key or at least calling the function with "extracted" and filtered dictionary in concise way)?

Answer 1

The problem you encountered is described here .
There is a trick to work around which looks fine to me.

{% macro some_macro(state_id, orig_name, download_url, archive_format, owner, archive_opts=None) -%}
{% if kwargs | length >= 0 -%}
// implement your macro definition here
{% endif -%}
{% endmacro -%}

The point is that you have to call kwargs if you didn't consume all the variables in mapping.

Then call your macro as :

{{ some_macro('some_state', **intellij) }}