编译时的顶级表达式评估

Question

Is there any way to ensure, that an expression like the following would be evaluated at compile time?

myList :: [Int]
myList = sort [3,2,0,1]

Answer 1

If what you're evaluating is an instance of Lift , you can evaluate it at compile time using TemplateHaskell :

{-# LANGUAGE TemplateHaskell #-}

module Sort where

import Data.List
import Language.Haskell.TH.Syntax

myList :: [Int]
myList = $(lift (sort [3,2,0,1] :: [Int]))

If you want, you can check what it has compiled to with -ddump-splices :

$ ghc -ddump-splices sort
[1 of 1] Compiling Sort             ( sort.hs, sort.o )
sort.hs:9:12-41: Splicing expression
    lift (sort [3, 2, 0, 1] :: [Int]) ======> [0, 1, 2, 3]