如何在使用React-Router＆Redux时单击链接时调度操作？

Question

Let's say I have a Link that sends me to a page for adding/editing a list entry.

How do I dispatch a Redux action when I click on the Link itself so that I can update the Redux store first, before actually getting redirected to that page.

Eg: I click on Edit button -> Action is dispatched -> Store updated, {'state': 'edit-mode'} -> Proceed to redirect.

Or do you have another way in mind to accomplish what I'm trying to do?

Maybe when component has mounted, then I will run an action like stateToEdit based on certain conditions? If so, then please show to me your way. Thanks

PS: I'm using only one component for all add/edit/delete. So I'm thinking of a way to render based on the state whether its on edit-mode or delete-mode etc.

Answer 1

Here are a couple ways you could go about addressing this issue:

1. Instead of using Link , try utilizing browserHistory.push(path) with an onClick function.
   • Inside the onClick , you can dispatch your action, then push to a new location.
   • However, if you want to perform this series of actions in various components, you will probably suffer from code duplication.
2. A more robust way to address this issue would be to implement redux-thunk , which provides a generic way of performing multiple "actions" (be it calling a Redux action, or performing an async operation, or both!) in response to a change.
   • Dan has a great response here highlighting the simplicity of what redux-thunk actually offers: Can I dispatch multiple actions without Redux Thunk middleware?
   • In your case, in the incrementTwice function, imagine just replacing one of the dispatch(increment) calls with a call to browserHistory.push(action.path) , similar to the below:

Redux thunk action

export const dispatchThenRoute = (myAction, myPath) => {
    return (dispatch) => {
        dispatch(myAction)
        browserHistory.push(myPath);
    }
};