[英]Is there any way to execute a SELECT only if a condition in a different table is met?
Is there any way to do that in a single query? 有没有办法在单个查询中做到这一点? Or do I have to manage it externally?
还是我必须从外部进行管理? It is not a JOIN of any kind.
它不是任何一种JOIN。
SELECT
IF (
(SELECT indicator FROM configuration_table) = 1,
(SELECT series_id FROM series_table LIMIT 1),
''
) as if_exp
FROM
series_table
This executes but returns the first ID over and over, and if I take out the LIMIT 1, it doesn't work as it expects only one result. 这将执行,但是一遍又一遍地返回第一个ID,如果我取出LIMIT 1,它将无法正常工作,因为它只期望一个结果。 But what I need is that, if this condition is met:
但是我需要的是,如果满足此条件:
(SELECT indicator FROM configuration_table) = 1,
Then I need all this data returned: 然后,我需要返回所有这些数据:
SELECT series_id, series_code, series_name FROM series_table
Is it possible somehow? 有可能吗? Should I be doing two queries and managing the data from php?
我应该做两个查询并管理来自php的数据吗? Thank you very much.
非常感谢你。
The easiest way would be: 最简单的方法是:
IF ((SELECT indicator FROM configuration_table) = 1) THEN
SELECT series_id, series_code, series_name FROM series_table
END IF
You did not show us what to do, when the condition is false. 当条件为假时,您没有告诉我们该怎么做。 We do not know the relationship between
configuration_table
and series_table
, so we can't find a way to make it in a single query. 我们不知道
configuration_table
和series_table
之间的关系,因此我们找不到在单个查询中实现该关系的方法。
I have copied this answer from IF Condition Perform Query, Else Perform Other Query this answer. 我已从“ 条件执行查询”中复制了此答案,“从其他条件执行此查询中复制了”。
SELECT CASE WHEN ( (SELECT indicator FROM configuration_table) = 1 )
THEN
SELECT series_id, series_code, series_name FROM series_table
ELSE
<QUERY B>
END
Here Query B
should replaced by your desired query. 在这里,
Query B
应该替换为您想要的查询。
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