使用curl命令将Java WebApp配置为通过http传输数据

Question

I'm currently running a webapp on tomcat 8 and wish to show the receive the output of a certain post request on the terminal screen without rendering a webpage. As an example, I'm looking to use a command similar to this:

curl -d "param1=xxx&param2=yyy" localhost:8080/webapp

and get a (short) response similar to this:

"some data here"

I do not want to get the HTML of a webpage that would be rendered if I hit the URL in a browser. Is there any way that this can be done in Tomcat?

Answer 1

AFAIK response content is generated in Tomcat by the web application (servlet, JSP or whatever). You probably should create such a webapp which will output just a text without a tags and other html stuff, fe create a index.jsp file in tomcat webapps root directory (usually tomcat_root\\webapps\\ROOT ) with this content (yes, just one short line):

<%="some data here"%>

You'll get raw data by this request, BUT this will anyway a HTTP response. If you plan to deal with this data on lower level (say TCP), you'll get from server extra data like headers values etc.

Additionally you probably have to care about setting correct headers in response, fe: ContentType: text/plain , if your client software cares about it. Or just skip it: you'll get raw text content anyway independently of content-type headers values.

Answer 2

您必须指定该请求是POST请求

$ curl -i -X POST  -d "param1=xxx&param2=yyy" localhost:8080/webapp