[英]Jquery setTimeout not working if used without alert
I am implementing this code. 我正在执行此代码。
$('.mcqtd').click(function(){
var choice = this.id;
checkanswer(choice,questions[x].correctAnswer);
window.setTimeout(showquestion(x+1,0),3000); // 1 seconds
});
}
function checkanswer(answer,original){
if (answer=='choice'+original){
$('#choice'+original).css('backgroundColor', '#DD792E');
$('#choice'+original).append("<span class='padding10 mcqsymbol'><img src='images/right_icon.png' /></span>");
} else {
$('#'+answer).css('backgroundColor', '#AFA689');
$('#'+answer).append("<span class='padding10 mcqsymbol'><img src='images/wrong_icon.png' /></span>");
$('#choice'+original).css('backgroundColor', '#DD792E');
$('#choice'+original).append("<span class='padding10 mcqsymbol'><img src='images/right_icon.png' /></span>");
}
}
Onclick
, the tds
should be highlighted, and after 3 seconds, the next question should be loaded but this is not happening, after 3 seconds the next question is being loaded, but backgrounds are not changing. Onclick
, tds
应该突出显示,并且3秒钟后,应该加载下一个问题,但这没有发生,3秒钟后,正在加载下一个问题,但是背景没有改变。 If I alert something inside checkanswer()
, the code works. 如果我在
checkanswer()
内checkanswer()
警报,则代码将起作用。 Any ideas what should I do? 有什么想法我该怎么办?
The to executing part must be wrapped in a anonymous function if you want to use parametes. 如果要使用参数,则to执行部分必须包装在匿名函数中。 Otherwise it is not working in
setTimeout
. 否则它在
setTimeout
不起作用。
setTimeout(function() {
showquestion(x + 1, 0);
}, 3000);
As A.Wolff noted in the comments below, you can even pass parameters to a called function in setTimeout
by extening the parameters behind the time. 正如A.Wolff在下面的注释中指出的那样,您甚至可以通过在时间后扩展参数来将参数传递给
setTimeout
的调用函数。
// note there are no '()' behind the function name
setTimeout(showquestion, 3000, x + 1, 0);
If you would call a function without parameters you can left out the wrapper function and the additional parameters too. 如果要调用不带参数的函数,则可以省略包装函数和其他参数。
// note there are no '()' behind the function name
setTimeout(functionWithoutParameter, 3000);
What you do is calling the function directly and passing it's return value over to setTimeout
. 您要做的就是直接调用该函数,并将其返回值传递给
setTimeout
。 As you intend to use arguments with this, you will have to make use of an anonymous function , eg: 当您打算为此使用参数时,您将必须使用匿名函数 ,例如:
setTimeout(function(){ showquestion(x+1, 0);}, 3000);
Edit: 编辑:
If you only have a functioncall without arguments it woulf look like: 如果只有一个不带参数的函数调用,它将看起来像:
setTimeout("foo()", 3000);
or 要么
setTimeout(foo, 3000);
Dirtly call this in setTimeout method its not working. 在setTimeout方法中直接调用它不起作用。
setTimeout(question, 3000);
function question() {
showquestion(x + 1, 0)
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.