在Mac OS X上从bash脚本调用时，php脚本无法运行

Question

Following is a bash script run.command that I am trying to use to call a PHP script

  #!/bin/bash
  #!/usr/bin/php
  # Main script 

php -f generateTest.php

Why does this not run when I "double click" the bash script ? It runs on calling from the terminal on OS X

I get the error message

asehgal-MacBook-Pro:~ asehgal$ /Users/asehgal/projects/configtest/run.command ; exit;
Could not open input file: generateTest.php
logout
Saving session...
...copying shared history...
...saving history...truncating history files...
...completed.

I have used chmod +x to make it executable.

Answer 1

Use the absolute path to your generateTest.php file and it should work, it's not working now because it's trying to find generateTest.php in your current working directory (where you are running run.command from)

Example:

#!/bin/bash
#!/usr/bin/php
# Main script 

php -f /Users/asehgal/projects/configtest/generateTest.php

Answer 2

cd -- "$(dirname "$BASH_SOURCE")"

This needs to be there after the shebang line. Thats because when the terminal opens to run a bash script, it defaults to the current users home directory. Hence, we need to change the path to the folder out of which we expect to run out of.