Java - 概括不同的类，类似的方法（不改变子类？）

Question

Not sure if this is possible, but I have a case in which two interfaces have the same method. These are interfaces that are given, so I can't change them.

Given Interfaces

interface SomeGivenService {
    boolean authenticate(String username, String password);
    Object someSpecialMethod(Object param);
}

interface AnotherGivenService {
    boolean authenticate(String username, String password);
    String aGreatMethod();
    String sayHello();
}

To consume this service, I created a class and did some handling in case this service throws an error.

class SomeGivenServiceConsumer {

    SomeGivenService a;

    public SomeGivenServiceConsumer(SomeGivenService a) {
        this.a = a;
    }

    public authenticate(MyUserPassBean bean) {
        try {
            a.authenticate(bean.username, bean.password);
        } catch (Exception e) {
            throw new MyException();
        }
        ...
    }
}

class AnotherGivenServiceConsumer {

    AnotherGivenService a;

    public AnotherGivenServiceConsumer(AnotherGivenService a) {
        this.a = a;
    }

    public authenticate(MyUserPassBean bean) {
        try {
            a.authenticate(bean.username, bean.password);
        } catch (Exception e) {
            throw new MyException();
        }
        ...
    }
}

Is it possible to avoid this code duplication in my consumers? I probably will have many of them and wanted to avoid this duplicated code. I initially thought of changing my consumer to receive an interface that implements this authentication, but as I can't change the given interfaces, not sure if this is even possible.

Is it possible to have a "Generic interface which has a method?" or use some design pattern? Any ideas? What I was trying:

class AnotherGivenServiceConsumer {

    AnotherGivenService a;
    GivenServiceAuthenticable b;

    public AnotherGivenServiceConsumer(AnotherGivenService a, 
                                       GivenServiceAuthenticable b) {
        this.a = a;
        this.b = b;
    }

    public authenticate(MyUserPassBean bean) throws MyException {
        return b.authenticate(bean.username, bean.password);
    }
}

interface GivenServiceAuthenticable<T> {
    boolean authenticate(T givenService, MyUserPassBean bean);
}

class GivenServiceAuthenticableImpl<T> implements GivenServiceAuthenticable<T> {
    boolean authenticate(T givenService, MyUserPassBean bean) {
        try {
            //this won't compile as it's a generic class..
            t.authenticate(bean.username, bean.password); 
        } catch (Exception e) {
            throw new MyException();
        }
        ...
    }
}

Other problem is how to instantiate this object if I can't change it to implement my new objects?

Answer 1

You can use the template pattern to implement the common functionality in a base class, while delegating the single varying line to subclasses:

abstract class ConsumerBase {
    public void authenticate(MyUserPassBean bean) {
        try {
            authenticate(bean.username, bean.password);
        } catch (Exception e) {
            throw new MyException();
        }
        //...
    }

    protected abstract boolean authenticate(String username, String password);
}

class SomeGivenServiceConsumer extends ConsumerBase {

    SomeGivenService a;

    public SomeGivenServiceConsumer(SomeGivenService a) {
        this.a = a;
    }

    @Override
    protected boolean authenticate(String username, String password) {
        return a.authenticate(username, password);
    }
}

class AnotherGivenServiceConsumer extends ConsumerBase {

    AnotherGivenService a;

    public AnotherGivenServiceConsumer(AnotherGivenService a) {
        this.a = a;
    }

    @Override
    protected boolean authenticate(String username, String password) {
        return a.authenticate(username, password);
    }
}

Answer 2

What you need to do is to use inheritance. Then deal with the error in the superclass ie

    class SomeGivenServiceConsumer {

        SomeGivenService a;
        AnotherGivenService b;

        public SomeGivenServiceConsumer(SomeGivenService a) {
            this.a = a;
            try{
             authenticate(MyUserPassBean);
            }catch (Exception e) {
            System.out.println("Thrown exception has been caught : "+e.getMessage());
            }
        }

        public authenticate(MyUserPassBean bean) throws MyException {
                //your implementation here
        }
    }    
    class AnotherGivenServiceConsumer extends SomeGivenServiceConsumer{

        public AnotherGivenServiceConsumer(AnotherGivenService b) {
            super(someGivenService);//construct superclass
            authenticate(MyUserPassBean);//call subclass authenticate method
        }

        @override
        public authenticate(MyUserPassBean bean) throws MyException {
                super.authenticate(MyUserPassBean);//call superclass method
                //your implementation here

        }
    }

then you construct the subclass:

public static void main(String[] args) {
    new AnotherGivenServiceConsumer(AnotherGivenService);
}