选择表中ID等于另一个表中另一个ID的行

Question

I would like to select a certain row in my getadvocacy table where id is the id in another table called swimsuit.

swimsuit table

id         |         name          |       average
1          |         Abc           |       90
3          |         Def           |       99

getadvocacy

id         |        all_scores     |       average_score
1          |        70,70,70       |       70
2          |        70,70,70       |       70
3          |        70,70,70       |       70

Now, I want to select from getadvocacy but only 1 and 3 because it is the data on swimsuit.

Expected Output

id         |        all_scores     |       average_score
1          |        70,70,70       |       70
3          |        70,70,70       |       70

I tried this but it has different output.

select getadvocacy.id, all_scores, average_score from getadvocacy WHERE getadvocacy.id IN (select id from swimsuit)

Answer 1

If the id (primary key) is same for table then you can use join on Id

 select * from table1
        JOIN table2 
             on table1.id = table2.id

Use this

  select * from swimsuit JOIN getadvocacy ON swimsuit.id= getadvocacy.id;

Result of query is

    1   abc 90  1   50,60,70    70
    3   def 99  3   60,70,70    70

Answer 2

in standard sql you have to do:

select * 
from getadvocacy
where
    id in (select st.id from "swimsuit table" as st)

Answer 3

Simplest and easier to understand: Just by reading between the lines, you will understand how this snippet works

SELECT getadvocacy.* , swimsuittable.*
FROM getadvocacy, swimsuittable
WHERE getadvocacy.id = swimsuittable.id