[英]Select rows in a table where id is equals to another id in another table
我想在我的getadvocacy表中選擇某一行,其中id是另一個表中的id,稱為Swimsuit。
泳衣桌
id | name | average
1 | Abc | 90
3 | Def | 99
宣傳
id | all_scores | average_score
1 | 70,70,70 | 70
2 | 70,70,70 | 70
3 | 70,70,70 | 70
現在,我要從getadvocacy中進行選擇,但只能選擇1和3,因為它是泳衣上的數據。
預期產量
id | all_scores | average_score
1 | 70,70,70 | 70
3 | 70,70,70 | 70
我試過了,但是它有不同的輸出。
select getadvocacy.id, all_scores, average_score from getadvocacy WHERE getadvocacy.id IN (select id from swimsuit)
如果表的ID(主鍵)相同,則可以在ID上使用join
select * from table1
JOIN table2
on table1.id = table2.id
用這個
select * from swimsuit JOIN getadvocacy ON swimsuit.id= getadvocacy.id;
查詢結果是
1 abc 90 1 50,60,70 70
3 def 99 3 60,70,70 70
在標准sql中,您必須執行以下操作:
select *
from getadvocacy
where
id in (select st.id from "swimsuit table" as st)
最簡單易懂:只需在兩行之間閱讀,您就會了解此代碼段的工作方式
SELECT getadvocacy.* , swimsuittable.*
FROM getadvocacy, swimsuittable
WHERE getadvocacy.id = swimsuittable.id
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