[英]MySql: insert into table SELECT from another table where first_table ID =another_table.id
我有這個起始表:
+----+-------------+---------+
| id | id_customer | balance |
+----+-------------+---------+
| 1 | 123 | NULL |
| 2 | 124 | NULL |
| 3 | 125 | NULL |
| 4 | 126 | NULL |
+----+-------------+---------+
我需要用另一個表中的SELECT SUM填充該balance
列,其中第一個表中的id_customer =第二個表中的id_customer。
+----+-------------+--------+------------+
| id | id_customer | amount | date_trans |
+----+-------------+--------+------------+
| 1 | 123 | 100 | 2018-01-01 |
| 2 | 123 | -10 | 2018-01-04 |
| 3 | 125 | 70 | 2018-01-01 |
| 4 | 124 | 10 | 1994-05-04 |
| 5 | 124 | 20 | 2018-01-01 |
| 6 | 126 | 10 | 2018-01-16 |
| 7 | 126 | 50 | 2018-04-16 |
+----+-------------+--------+------------+
第二個表的條件是“ 2010-01-01”和“ 2018-02-28”之間的date_trans的總和(金額)。
因此,在我的示例中,我需要最終的第一個表為:
+----+-------------+---------+
| id | id_customer | balance |
+----+-------------+---------+
| 1 | 123 | 90 |
| 2 | 124 | 20 |
| 3 | 125 | 70 |
| 4 | 126 | 10 |
+----+-------------+---------+
id 2僅20,因為id 4處的10 $交易超出范圍。 id 4僅10,因為id 7的50 $交易超出范圍。
這是從second_table中提取SUM的(簡單)查詢。
SELECT id_customer , SUM(balance) AS saldo FROM second_table
WHERE date_trans BETWEEN '2010-01-01 00:00:00' AND '2018-02-28 23:59:59'
GROUP BY id_customer
通過該查詢,我還有幾個ID(〜99400)對我來說並不有趣,因此我需要執行類似的偽代碼:
INSERT INTO first_table ( balance )
SELECT saldo FROM
( SELECT id_customer , SUM(balance) AS saldo FROM second_table
WHERE date_trans BETWEEN '2010-01-01 00:00:00' AND '2018-02-28 23:59:59'
GROUP BY id_customer )
WHERE first_table.id_customer = second_table.id_customer
我不能使用“ IN”,因為第二個表大約有100.000行。 起始桌約600張。
只需在UPDATE語句的SET子句中使用一個(相關的)子查詢即可:
UPDATE first_table t1
SET t1.balance = (
SELECT SUM(t2.amount)
FROM second_table t2
WHERE t2.date_trans BETWEEN '2010-01-01 00:00:00' AND '2018-02-28 23:59:59'
AND t2.id_customer = t1.id_customer
);
嘗試這個
update first_table
set balance = sum(B.Balance)
from first_table A
inner join second_table B on (A.id_customer = B.id_customer
and (B.date_trans BETWEEN '2010-01-01 00:00:00' AND '2018-02-28 23:59:59'))
group by B.id_customer
嘗試這個:
UPDATE first_table A JOIN (SELECT id_customer, SUM(amount) total_amount
FROM second_table
WHERE date_trans BETWEEN '2010-01-01 00:00:00'
AND '2018-02-28 23:59:59'
GROUP BY id_customer) B
ON A.id_customer=B.id_customer
SET A.balance=B.total_amount;
看到它在SQL Fiddle上運行。
有關見解,請參見MySQL UPDATE JOIN教程。
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