[英]Why am I unable to send HTTP Headers to Flask-RESTful reqparse module using add_argument()?
I am trying to integrate the Flask-RESTful's request parsing interface, reqparse in my backend to request HTTP headers from the client. 我正在尝试集成Flask-RESTful的请求解析接口,在我的后端reqparse来请求来自客户端的HTTP头。 Currently, I wish to use this for authentication of a user and wish to pass 'secret_key'
in HTTP headers. 目前,我希望使用它来验证用户并希望在HTTP标头中传递'secret_key'
。
The function I am using for this task is the add_argument()
function. 我用于此任务的函数是add_argument()
函数。 My code for requesting the header is as follows: 我请求标题的代码如下:
reqparse = reqparse.RequestParser()
reqparse.add_argument('secret_key', type=str, location='headers', required=True)
However, on sending the following cURL request: 但是,在发送以下cURL请求时:
curl -H "Content-Type: application/json" -H "{secret_key: SECRET}" -X POST -d '{}' http://localhost:5000/authUser
I recieve the following 400 error on my Pycharm Community edition editor : 我在Pycharm社区版编辑器上收到以下400错误:
127.0.0.1 - - [02/Aug/2016 18:48:59] "POST /authUser HTTP/1.1" 400 -
and the following message on my cURL terminal: 以及我的cURL终端上的以下消息:
{
"message": {
"secret_key": "Missing required parameter in the HTTP headers"
}
}
To reproduce this error on Pycharm (and hopefully all other compilers as well), please use the files written below as follows: 要在Pycharm上重现此错误(并希望所有其他编译器也是如此),请使用下面编写的文件,如下所示:
Folder - Sample_App
- __init__.py
- run.py
- views.py
__init__.py __init__.py
from flask import Flask
from flask_restful import Api
from views import AuthUser
app = Flask(__name__)
api = Api(app)
api.add_resource(AuthUser, '/authUser')
views.py views.py
from flask_restful import reqparse, Resource
class AuthUser(Resource):
def __init__(self):
self.reqparse = reqparse.RequestParser()
self.reqparse.add_argument('secret_key', type=str, location='headers', required=True)
def post(self):
data = self.reqparse.parse_args()
if data['secret_key'] == "SECRET":
print("Success")
return 200
return 400
run.py run.py
from __init__ import app
app.run(host='0.0.0.0', port=5000, debug=True)
Could you please tell me how to fix this issue? 你能告诉我如何解决这个问题吗? I want to know if the location
parameter needs to be changed or if there is something wrong in my cURL request. 我想知道是否需要更改location
参数或者我的cURL请求中是否有错误。
EDIT: 编辑:
With the help of Methika's response, I have figured out the error. 在Methika的回应的帮助下,我发现了错误。 The add_argument()
function does not take _
in a headers parameter. add_argument()
函数不在headers参数中使用_
。 However, when I use the requests.headers['secret_key']
function, I am able to request headers with the _
character just fine. 但是,当我使用requests.headers['secret_key']
函数时,我可以请求带有_
字符的标题。 Why is that the case? 为什么会这样?
New Code of views.py : 新的views.py代码:
views.py views.py
from flask_restful import reqparse, Resource
class AuthUser(Resource):
def __init__(self):
self.reqparse = reqparse.RequestParser()
def post(self):
data = self.reqparse.parse_args()
data['secret_key'] = request.headers['secret_key']
if data['secret_key'] == "SECRET":
print("Success")
return 200
return 400
I did some tests with the code you gave here and I found out that the problem doesn't come from you code but from the name of the variable: 我用你在这里给出的代码做了一些测试,我发现问题不是来自你的代码,而是来自变量的名称:
If you replace secret_key
by secretkey
(or something else without underscore) it will work ! 如果更换secret_key
通过secretkey
(或别的东西,没有下划线),它的工作!
I found this post , flask seems to not accept underscores in header variable names. 我发现这个帖子 ,烧瓶似乎不接受标题变量名称中的下划线。
Instead of this curl request 而不是这个卷曲请求
curl -H "Content-Type: application/json" -H "{secret_key: SECRET}" -X POST -d '{}' http://localhost:5000/authUser
Try this one 试试这个吧
curl -H "Content-Type: application/json" -H "secret_key: SECRET" -X POST -d '{}' http://localhost:5000/authUser
In header normally I have seen using value like "Key: Value" 在标题中我通常看到使用像“Key:Value”这样的值
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