NumPy数组15分钟值-每小时平均值

Question

I have the following situation:

A numpy array

x = np.array([12,3,34,5...,])

where every entry corresponds to a simulation result (time-step 15min).

Now I need the mean hourly value (mean value of first 4 elements, then next 4, etc.) stored in a new numpy array. Is there a very simple method to accomplish this?

Answer 1

To handle arrays whose size may not be a multiple of 4, copy x into a new array, tmp , whose size is a multiple of 4:

tmp = np.full((((x.size-1) // 4)+1)*4, dtype=float, fill_value=np.nan)
tmp[:x.size] = x

Empty values are represented by nan . Then you can reshape and use nanmean to compute the mean for each row. np.nanmean is like np.mean except that it ignores nan s:

---

x = np.array([12,3,34,5,1])
tmp = np.full((((x.size-1) // 4)+1)*4, dtype=float, fill_value=np.nan)
tmp[:x.size] = x
tmp = tmp.reshape(-1, 4)
print(np.nanmean(tmp, axis=1))

prints

[ 13.5   1. ]

---

If you have pandas installed, then you could build a timeseries and group by a time interval:

import numpy as np
import pandas as pd
x = np.array([12,3,34,5,1])
s = pd.Series(x, index=pd.date_range('2000-1-1', periods=x.size, freq='15T'))
result = s.groupby(pd.TimeGrouper('1H')).mean()
print(result)

yields

2000-01-01 00:00:00    13.5
2000-01-01 01:00:00     1.0
Freq: H, dtype: float64

Answer 2

N = 4
mod_ = x.size % N
x1 = np.pad(x.astype(float), (0, (mod_ > 0) * (N - mod_)), 'constant', constant_values=(np.nan,))
x2 = np.reshape(x1, (int(x1.size/4), 4))
x3 = np.nanmean(x2, axis=1)
print(x3)

Answer 3

Here is another solution:

your input:

In [11]: x = np.array([12, 3, 34, 5, 1, 2, 3])

taking every 4 elements in b

In [12]: b = [x[n:n+4] for n in range(0, len(x), 4)]

create new empty list to append results

In [13]: l = []

In [14]: for i in b:
   ....:     l.append(np.mean(i))
   ....:     

In [15]: l
Out[15]: [13.5, 2.0]