直角三角形可能吗？

Question

Given h , the hypotenuse and s , the surface area, it is asked to print the sides of the right angle triangle if possible, else print -1 . So here was my approach;

   double h,s;
   scanf("%lf %lf",&h,&s);
   s*=4;
   double squaresum=(h*h) + s;
   double squarediff=(h*h) - s;
   if(squarediff<0)
       printf("-1\n");
   else
   {
       double a = sqrt(squaresum)+sqrt(squarediff);
       a/=2;
       double b = sqrt(squaresum)-sqrt(squarediff);
       b/=2;
       if(h>=a+b)
            printf("-1\n");
       else
        printf("%.6lf %.6lf %.6lf\n",h,a,b);
   }

My approach:
Given s , if we multiply 4 , then it is 2*a*b , where a and b are the other sides of the triangle. Then I find (a+b)^2 and (ab)^2 as I have h*h=a^2+b^2 . It even passed the custom test case:

4
5 6
6 10
258303 89837245228
616153 77878145466

Output:

4.000000 3.000000 5.000000
-1
-1
546189.769984 285168.817674 616153.000000

But the answer is being judged as wrong. I am not able to pick up how the answer could go wrong given 0<=h<=10^9 and 0<=s<=10^12 . The problem link-
https://www.codechef.com/problems/RIGHTTRI

Answer 1

Maybe I'm wrong, but if I read the Output required :

Output the answer for each test-case in a single line. If it is not possible to find such a triangle, output -1. Otherwise print 3 real numbers corresponding to the lengths of the sides of the triangle sorted in non-decreasing order . Please note that the length of the triangle sides should not differ by more than 0.01 in absolute value from the correct lengths.

Your output is not sorted... I guess non-decreasing order means increasing order... Maybe give it a shot before anything else...

(Edited question according to comment) :

non-decreasing order means you must sort them number from the lowest to the highest, by length :

3.000000 4.000000 5.000000

Mainly the issue with math problems is to understand what they want from you...