C 程序输入三个整数，看它们是否构成一个三角形和一个直角

Question

I was given a question from an assignment that asks me to make a program where the user enters 3 integers and then it checks to see if they can be sides of a triangle. I am supposed to use a nested if statement for this, I cannot use && in the statements and the formula they gave me is

num1 < num2 + num3 AND num1 < num2 - num3 

I am very confused on this and any help would be appreciated!

Answer 1

The question appears to be asking how to implement a logical AND using nested if statements rather than && operators.

if (X && Y) foo; is equivalent to if (X) if (Y) foo; .

Answer 2

int a=1, b=2, c=3;
if (a<b+c)
{
    if (a<b-c)
        printf("Yes");
}

Answer 3

if (num1 < num2 + num3)       /* if this is true you enter the first scope */
{
    if (num1 < num2 - num3)   /* if this is also true enter the second scope */
    {
        printf("TRUE\n");
    }
}